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3 years ago

15

Kim has a living room that measures 12 feet by 12 feet. She wants to buy the largest circular area rug that she can find for the

room.
There are four rugs at a local department store. Which rug should she buy?

4 foot radius?

6 foot radius?

8 foot radius?

10 foot radius?

1 answer:

galina1969 [7]3 years ago

8 0

Answer: 10 foot radius

Step-by-step explanation:

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The graph below shows the distribution of students grades on their last math test. Based on the Empirical rule, what percent of

timurjin [86]

Based on the emperical rule
the distribution will be as follows

btwn 80 n 85 on the test - 34%
btwn 80 n 95 on the test - 82%
below 85 on the test - 50%
<span>above an 80 on the test - 84%</span>

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3 years ago

Help, i've been trying for around 30mins and I can't figure it out.

omeli [17]

Answer:

<h2><em><u>Option</u></em><em><u> </u></em><em><u>A</u></em><em><u> </u></em><em><u>and</u></em><em><u> </u></em><em><u>C</u></em></h2>

Step-by-step explanation:

As,

$2 \sqrt{75} + 3 \sqrt{50}$

$= 2 \sqrt{25 \times 3} + 3 \sqrt{25 \times 2} (A)$

$= 2 \times 5 \sqrt{3} + 3 \times 5 \sqrt{2}$

$= 10 \sqrt{3} + 15 \sqrt{2} (C)$

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3 years ago

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Harold spent 3/4 hour milking cows. He milked 3 groups of cows. If he spent an equal amount of time on each group of cows, what

Aneli [31]

(3/4)/3

3/12

1/4

So he spent a 1/4 hour milking each group.

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3 years ago

Divide the combinations.<br><br> 60C3 / 15C3

Mariulka [41]

I hope you know what '!' means
2!=2
3!=6
4!=24
basicalkly times every natural number including and before that number

nCr= $\frac{n!}{r!(n-r)!}$
so
$\frac{60C3}{15C3}$ =
$\frac{ \frac{60!}{3!(60-3)!} }{ \frac{15!}{3!(15-3)!} }$ =
$( \frac{60!}{3!(60-3)!})(\frac{3!(15-3)!}{15!})$ =
$( \frac{60!}{3!(57)!})(\frac{3!(12)!}{15!})$ =
$\frac{(60!)(3!)(12!)}{(3!)(57!)(15!)}$ =
$\frac{(60!)(12!)}{(57!)(15!)}$ =
$\frac{(60!)}{(57!)(15)(14)(13)}$ =
$\frac{(60)(59)(58)}{(15)(14)(13)}$ =
$\frac{(30)(59)(58)}{(15)(7)(13)}$ =
$\frac{(6)(59)(58)}{(3)(7)(13)}$ =
$\frac{6844}{91}$

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3 years ago

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Which set of rectangular coordinates describes the same location as the polar coordinates (6sqrt 2, 3pi/4)

Sonja [21]

Polar coordinates=<span>(6sqrt 2, 3pi/4)=(r, theta)→r=6 sqrt 2, theta=3pi/4
Rectangular coordinates=(x,y)=?

x=r cos theta=(6 sqrt 2) cos(3pi/4)=(6 sqrt 2)(-sqrt 2 / 2)
x=-3 (sqrt 2)^2=-3(2)→x=-6

y=r sin theta=(6 sqrt 2) sin (3pi/4)=(6 sqrt 2)(sqrt 2 / 2)
y=3 (sqrt 2)^2=3(2)→y=6

Rectangular coordinates of the point = (x,y) =(-6,6)

Answer: Option a. (-6,6) </span>

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3 years ago