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3 years ago

If 0

Mathematics

1 answer:

telo118 [61]3 years ago

7 0

The correct answer is A

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What is the average of 140, 130, 144, 145, 130?

diamong [38]

The average is 137.8.

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3 years ago

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Which of the following scatterplots represents the data shown below?

AleksAgata [21]

Answer:

Step-by-step explanation:

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3 years ago

PLEASE!!!!! HELP ME!!!!!!

kati45 [8]

Answer:

$15 = a_1 r^4$ (1)

$1 = a_1 r^5$ (2)

If we divide equations (2) and (1) we got:

$\frac{r^5}{r^4}= \frac{1}{15}$

And then $r= \frac{1}{15}$

And then we can find the value $a_1$ and we got from equation (1)

$a_1 = \frac{15}{r^4} = \frac{15}{(\frac{1}{15})^4} =759375$

And then the general term for the sequence would be given by:

$a_n = 759375 (\frac{1}{15})^n-1 , n=1,2,3,4,...$

And the best option would be:

C) a1=759,375; an=an−1⋅(1/15)

Step-by-step explanation:

the general formula for a geometric sequence is given by:

$a_n = a_1 r^{n-1}$

For this case we know that $a_5 = 15, a_6 = 1$

Then we have the following conditions:

$15 = a_1 r^4$ (1)

$1 = a_1 r^5$ (2)

If we divide equations (2) and (1) we got:

$\frac{r^5}{r^4}= \frac{1}{15}$

And then $r= \frac{1}{15}$

And then we can find the value $a_1$ and we got from equation (1)

$a_1 = \frac{15}{r^4} = \frac{15}{(\frac{1}{15})^4} =759375$

And then the general term for the sequence would be given by:

$a_n = 759375 (\frac{1}{15})^n-1 , n=1,2,3,4,...$

And the best option would be:

C) a1=759,375; an=an−1⋅(1/15)

4 0

3 years ago

The area of a square is 100. The length of its diagonal is approximately:

mr_godi [17]

Answer:

10 $\sqrt{2\\} \\$ or 14.14 appromiximately

Step-by-step explanation:

Area of square = 100

So length on side = 10 because all sides of square equal.

Length of Diagonal = Side x $\sqrt{2}$

So the length of diagonal is 14.14 approximately

6 0

2 years ago

3x+4y-3z=4;5x-y+2z=3;x+2y-z=-2 Solving Systems in three variables

Harlamova29_29 [7]

Answer: x = 3, y = 1, z = 2

Step-by-step explanation:

EQ 1: x - y - z = 0

EQ 3: -x + 2y + z = 1

y = 1

EQ 2: 2x - 3y + 2z = 7 → 1(2x - 3y + 2z = 7) → 2x - 3y + 2z = 7

EQ 3: -x + 2y + z = 1 → -2( -x + 2y + z = 1) → -2x + 4y + 2z = 2

y + 4z = 9

y = 1 ⇒ 1 + 4z = 9

4z = 8

z = 2

Input y = 1 and z = 2 into one of the equations to solve for x:

EQ 1: x - y - z = 0

x - (1) - (2) = 0

x - 3 = 0

x = 3

Check:

EQ 2: 2x - 3y + 2z = 7

2(3) - 3(1) + 2(2) = 7

6 - 3 + 4 = 7

3 + 4 = 7

7 = 7 $\checkmark$

6 0

3 years ago