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evablogger [386]
2 years ago
5

To summarize what you have learned in this lesson, answer the questions below:

Mathematics
1 answer:
DerKrebs [107]2 years ago
4 0

Answer:

<em>sorry i don't know the answer:(</em>

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Um oh that’s stealing
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If i have 20 cookies and i take 10 away, how much do i have left
pentagon [3]

Answer:

10

Step-by-step explanation:

20 - 10 = 10

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Let f(x) = 8x3 − 28x + 61 and g(x) = 2x + 5. Find f of x over g of x.
antoniya [11.8K]

Answer:

4x^2-10x+11+\frac{6}{2x+5}

Step-by-step explanation:

The given functions are:

f(x)=8x^3-28x+61 and g(x)=2x+5

By algebraic properties of functions;

\frac{f(x)}{g(x)}=\frac{8x^3-28x+61}{2x+5}

We perform the long division of the two polynomials as shown in the attachment.

Therefore:

\frac{8x^3-28x+61}{2x+5}=4x^2-10x+11+\frac{6}{2x+5}

The last choice is correct

8 0
2 years ago
30 points!!!
kykrilka [37]

Answer:

no idea to anybody help him

8 0
3 years ago
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If 0°&lt;0&lt;90° and sin0=12/13, find cos0 using trigonometric identities.
Aleks04 [339]

here's the solution,

we know :

\sin( \theta)  =  \dfrac{perpendicular}{hypotenuse}

So,

\dfrac{p}{h}  =  \dfrac{12}{13}

so.. let the perpendicular be 12x and hypotenuse be 13x

now,

by applying pythagoras theorem,

  • b {}^{2}  = h {}^{2}  - p {}^{2}

where,

  • b = base
  • h = hypotenuse
  • p = perpendicular

So,

  • b {}^{2}  =  ({13x})^{2}  -  ({12x})^{2}
  • b  {}^{2} = 169x {}^{2}  - 144x {}^{2}
  • {b}^{2}  = 25x {}^{2}
  • b  = 5x

so,

  • \cos( \theta)  =  \dfrac{b}{h}

  • \cos( \theta)  =   \dfrac{5x}{13x}

  • \cos( \theta)  =  \dfrac{5}{13}

hope it helps !!

3 0
3 years ago
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