I am pretty sure the answer is H
At the point when Hannah takes her first sweet from the sack, there is a 6/n chance it is orange.
This is because that there are 6 orange desserts and n desserts altogether.
When Hannah takes out her second sweet, there is a 5/(n-1) chance that it is orange.
This is because there are just 5 orange desserts let alone for an aggregate of n-1 desserts.
The possibility of getting two orange desserts in succession is the main likelihood increased by the second one: 6/n x 5/n–1
The question lets us know that the shot of Hannah getting two orange desserts is 1/3.
So: 6/n x 5/n–1 = 1/3
Now, rearrange this problem.
(6x5)/n(n-1) = 1/3
This gets to be:
30/(n² – n) = 1/3
Times by 3 on both sides:
90/(n² – n) = 1
What's more, doing likewise with (n² – n):
So (n² – n) = 90
Our answer is: n² – n – 90 = 0
(16+5)4÷2=42
21×4÷2=42
84÷2=42
42=42
that is were to but you answer
Second: $500,000
Third: $250,000
Fourth: $125,000
Fifth: $62,500
Sixth:$31,250
Seventh:$15,625
If you need the total just add
Answer:
w is the length
Step-by-step explanation:
length squared is always the area of a square
