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3 years ago

Hey can someone help me with this problem?

Mathematics

1 answer:

Sindrei [870]3 years ago

6 0

(f - g(x) = 2x -2x squared

(sorry didn't know how to do the squared sign )

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If two people have a 10% chance of winning what is there combines chance

erica [24]

Their combined chance of winning is 20%.

6 0

3 years ago

Marcella had $15. She bought some books. After that she had $6 left.

KengaRu [80]

Answer:

B.) 15 - A = 6

Step-by-step explanation:

The equation shows that Marcella had $15 then bought something (A), and now she has 6 dollars left.

15 - A = 6

8 0

4 years ago

Read 2 more answers

REPRESENT A PROBLEM: Six friends share 5 meat pies. Each friend first eats half of a meat pie. How much more meat pie does each

lord [1]

I cannot draw a picture, you can.

6 friends multiplied by 1/2 a pie each is 3 pies. That leaves 2 pies to divide evenly among 6 friends. 2/6 = 1/3. One third more pie more for everyone.

7 0

3 years ago

A high school runs a survey asking students if they participate in sports. The results are found below. Run an independence test

Sveta_85 [38]

Answer:

It can be concluded that participation in sports is dependent on grade level.

Step-by-step explanation:

In this case a Chi-square independence test for the data is to be performed at α = 0.01.

The hypothesis can be defined as follows:

H₀: The participation in sports is independent of grade level.

Hₐ: The participation in sports is dependent of grade level.

The data provided is:

Freshmen Sophomores Juniors Seniors

Yes 75 88 55 42

No 30 28 38 40

The formula to compute the expected frequencies is:

$E_{i}=\frac{i^{th}\ \text{Row Total}\ \times\ i^{th}\ \text{Column Total}}{N}$

The Chi-square statistic is:

$\chi^{2}=\sum {\frac{(O_{i}-E_{i})^{2}}{E_{i}}}$

Consider the Excel file attached below.

The value of Chi-square statistic is 16.244.

The degrees of freedom of the test are:

$\text{df}=(r-1)(c-1)$

$=(4-1)(2-1)\\=3\times 1\\=3$

Compute the p-value of the test as follows:

$p-value=P(\chi^{2}_{df}$

$=P(\chi^{2}_{3}$

*Use a Chi-square table.

p-value = 0.001 < α = 0.01

The null hypothesis will be rejected at 1% level of significance.

Thus, it can be concluded that participation in sports is dependent on grade level.

4 0

4 years ago

Anyone know how to do this?

Airida [17]

Answer:

K is equal to 56

Step-by-step explanation:

7 0

3 years ago