Answer: Cool. They must have been unique if it was only 5
Step-by-step explanation:
The 31st term of this sequence is 189.
9, 15, 21, 27, 33 (5), 39, 45, 51, 57, 63 (10), 69, 75, 81, 87, 93 (15), 99, 105, 111, 117, 123 (20), 129, 135, 141, 147, 153 (25), 159, 165, 171, 177, 183 (30), 189.
Answer: 1 1/2
Step-by-step explanation:
None of the <em>three</em> points (A, B, C) lies on the circumference of the <em>unit</em> circle.
<h3>What point is in the circumference of an unit circle?</h3>
<em>Unit</em> circles are circles centered at the origin and with a radius of 1. A point is on the circumference if and only if the distance of the point respect to the origin is equal to 1. The distance of each point is determine by Pythagorean theorem:
Point A
![d = \sqrt{4^{2}+3^{2}}](https://tex.z-dn.net/?f=d%20%3D%20%5Csqrt%7B4%5E%7B2%7D%2B3%5E%7B2%7D%7D)
d = 5
Point B
![d = \sqrt{\left(\frac{1}{2} \right)^{2}+\left(\frac{1}{5}\right)^{2} }](https://tex.z-dn.net/?f=d%20%3D%20%5Csqrt%7B%5Cleft%28%5Cfrac%7B1%7D%7B2%7D%20%5Cright%29%5E%7B2%7D%2B%5Cleft%28%5Cfrac%7B1%7D%7B5%7D%5Cright%29%5E%7B2%7D%20%7D)
d = √29 /10
d ≈ 0.539
Point C
![d = \sqrt{\left(\frac{3}{4} \right)^{2}+\left(\frac{7}{4} \right)^{2}}](https://tex.z-dn.net/?f=d%20%3D%20%5Csqrt%7B%5Cleft%28%5Cfrac%7B3%7D%7B4%7D%20%5Cright%29%5E%7B2%7D%2B%5Cleft%28%5Cfrac%7B7%7D%7B4%7D%20%5Cright%29%5E%7B2%7D%7D)
d = √58 /4
d ≈ 1.904
None of the <em>three</em> points (A, B, C) lies on the circumference of the <em>unit</em> circle.
<h3>Remark</h3>
The statement presents a typing mistake, correct form is shown below:
<em>A(x, y) = (4, 3), B(x, y) = (1/2, 1/5), C(x, y) = (3/4, 7/4). Which point lies on the circumference of the unit circle?</em>
To learn more on circles: brainly.com/question/11987349
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Answer:
15
Step-by-step explanation:
The amount of zeros of a function depends on the highest degree of such function.
Since the highest degree of the given polynomial is 15, hence the function will have 15 zeros