Using the information given, it is found that the class width for this frequency distribution table is of 1.
In this problem, these following classes are given:
0 – 1 14
2 – 3 1
4 – 5 8
6 – 7 12
8 – 9 12
The classes not given, which are 1 - 2, 3 - 4 and 5 - 6, have values of 0.
The <u>difference between the bounds of the classes is of 1</u>, thus, the class width is of 1.
A similar problem is given at brainly.com/question/24701109
Answer:
-4d
Step-by-step explanation:
L.c.m=15
15×2/5(d-10)-2/3×15(d+6)
3×2(d-10)-2×5(d+6)
6(d-10)-10(d+6)
6d-60-10d-60
6d-10d-60-60
-4d-0
-4d
48 pounds/1 * 1 kg/2.2 pounds=<span>21.82 kg
amanda weighs 21.82 kg, so the amount of medication that needs to be administered should be 21.82 mg.</span>
