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OLga [1]
3 years ago
7

A rectangle is 6 ft long and 11 ft wide. What is the length of the diagonal of the rectangle?

Mathematics
2 answers:
Natali5045456 [20]3 years ago
6 0

Answer:

sqrt(157) ft is the length of the diagonal

Step-by-step explanation:

We can use the Pythagorean theorem to find the length of the diagonal

a^2 + b^2 = c^2

6^2 + 11 ^2 = c^2

36+ 121 = c^2

157 = c^2

Take the square root of each side

sqrt(157) = sqrt(c^2)

sqrt(157) = c

statuscvo [17]3 years ago
6 0

Answer:

sqrt(157) ft is the length of the diagonal

Step-by-step explanation:

We can use the Pythagorean theorem to find the length of the diagonal

a^2 + b^2 = c^2

6^2 + 11 ^2 = c^2

36+ 121 = c^2

157 = c^2

Take the square root of each side

sqrt(157) = sqrt(c^2)

sqrt(157) = c

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ANSWER

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EXPLANATION

The volume of a cone is calculated using the formula:

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The height of the cylinder is also given as: h=18 in.

We substitute, the given values into the formula to get:

2279.64=  \frac{1}{3}  \times (3.14) \times {r}^{2}  \times 18

2279.64= 18.84 {r}^{2}

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{r}^{2}  = 121

We take positive square root to get;

r =  \sqrt{121}

r = 11in

Therefore the diameter is 2(11) which is equal to 22 inches.

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