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barxatty [35]
2 years ago
14

Prove that if a quadrilateral has four equal sides and one right angle, then the quadrilateral is a square

Mathematics
1 answer:
mars1129 [50]2 years ago
3 0
So lets ABCD are the sides of the square and AB=CD, AC=BD and the Angle ABC = 90 so therefore by making a diagonal we can use the SAS or SSS congruency for two triangles, so we can prove two triangles are equal and that is why the shape is square.
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Erin writes the set of ordered pairs below. The set represents a function.
tino4ka555 [31]
Point A shows that she is incorrect.
With functions, you can perform the "straight line test through each point. If the line goes through both points, you know it's not a function.
If we plotted point A, it'd fail the straight line test because the given point (-6, 7) already has -6 as an x value.
Hope this helps!
7 0
2 years ago
For the function f(x)=x2-4, fins the value of f(x) when x=6
garri49 [273]

f(x)=x^2-4\\f(6)=6^2-4\\f(6)=32

OR

f(x)=x*2-4\\f(6)=6*2-4\\f(6)=8

P.S. Hello from Russia

7 0
2 years ago
Read 2 more answers
If both diagonals of a quadrilateral bisect each other when is the quadrilateral a parallelogram?
slamgirl [31]
It is more than just a quadrilateral. In fact it is going to be hard to pick.

These facts suit a square,  a rectangle, a rhombus, and a parallelogram. And the above statement is true, but maybe a little harder to prove than the converse of the statement, which is the usual one you find.

The converse is "If you have a parallelagram, the diagonals bisect each other."

You might think a trapezoid deserves some mention. The diagonals of a trapezoid do not bisect each other.
6 0
2 years ago
What is the exact length of each side?
Alla [95]

Answer:

6a^{2} \sqrt{ab}

Step-by-step explanation:

area of square = side x side

thus, each side = square root of area

\sqrt{36a^5b} = 6\sqrt{a^{4} ab} = 6a^{2}\sqrt{ab}

6 0
2 years ago
Write three consecutive numbers starting with number n+1, where n is natural number. Find the sum of those numbers and prove tha
netineya [11]

Consecutive numbers differ by one, which means that if you start with a certain integer x, you obtain the next integer by adding one.

So, if you start with n+1, the three consecutive numbers are

n+1,\quad (n+1)+1 = n+2,\quad (n+2)+1 = n+3

The sum of these three numbers is

(n+1) + (n+2) + (n+3) = 3n+6

This number is divisible by 3 because you can write it as

3n+6 = 3(n+2)

Note that this is true in general: the sum of three consecutive numbers is always divisible by three, because it is three times the middle number.

5 0
2 years ago
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