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3 years ago

If the sum of three consecutive terms of GP are k-4,k,k+5. Find k

Mathematics

1 answer:

labwork [276]3 years ago

7 0

Answer:

k = 20

Step-by-step explanation:

t1 = a = k-4

a = k - 4

t2 = ar = k

(k-4)r = k - 4

r = k/(k-4)

t3 = ar^2 = k + 5

(k - 4)(k/k - 4)^2 = k+5

k^2/k-4 = k+5

k^2 = (k+5)(k-4)

k^2 = k^2 -4k +5k -20

0 = k -20

k =20

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Jake is buying a piece of recycled art from Luna. He started by giving her $50 and promised to pay her $5 a week until he pays t

garri49 [273]

Answer: $t = 50 + 5 w$

Step-by-step explanation:

Here w shows the number of weeks and t shows the total amount in w weeks.

Since, the initial amount he paid to her = $ 50

After that he paid $ 5 per week.

Thus, the total extra amount he paid = 5 w

⇒ The total amount he paid to her = 50 + 5 w

⇒ t = 50 + 5 w

Which is the required relation between the total amount paid(t) and the number of weeks (w) Jake will take to pay Luna.

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3 years ago

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Consider 10 married couples. how many ways can 7 married couples be selected from this group

Novay_Z [31]

10c7
=10!/(7!*(10-7)!)
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3 years ago

There is a bag with 50 popsicles inside. 5

Allisa [31]

Answer:

25%

Step-by-step explanation:

We know that there are ten purple popsicles. Together without the purple popsicles, there are 40 popsicles in total. Therefore there is a 10/40 chance to get purple. We need to turn this into a percentage so we do (10 / 40) x 100. This would equal to 25%, therefore, there is a 25% probability to get a purple popsicle.

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3 years ago

If the temperature after 4.4 degree drop was -2.5 degrees Celsius what was the temperature at noon

Lostsunrise [7]

Answer:

1.9°C

Step-by-step explanation:

Let X be the temperature at noon and -2.5°C be the current temperature after the drop.

-We calculate temperature at noon as:

$\bigtriangleup =t_o-t_n\\4.4=X--2.5\\\\X=4.4-2.5\\\\=1.5\textdegree C$

Hence, the temperature at noon was 1.9°C

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3 years ago

Two points on L1 and two points on L2 are given. Use the slope formula to determine if lines L1 and L2 are parallel, perpendicul

vlada-n [284]

Answer:

The lines L1 and L2 neither parallel nor perpendicular

Step-by-step explanation:

* Lets revise how to find a slope of a line

- If a line passes through points (x1 , y1) and (x2 , y2), then the slope

of the line is $m=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}$

- Parallel lines have same slopes

- Perpendicular lines have additive, multiplicative slopes

( the product of their slopes is -1)

* Lets solve the problem

∵ L1 passes through the point (1 , 10) and (-1 , 7)

- Let (1 , 10) is (x1 , y1) and (-1 , 7) is (x2 , y2)

∴ x1 = 1 , x2 = -1 and y1 = 10 , y2 = 7

∴ The slope of L1 is $m1 = \frac{7-10}{-1-1}=\frac{-3}{-2}=\frac{3}{2}$

∵ L2 passes through the point (0 , 3) and (1 , 5)

- Let (0 , 3) is (x1 , y1) and (1 , 5) is (x2 , y2)

∴ x1 = 0 , x2 = 1 and y1 = 3 , y2 = 5

∴ The slope of L2 is $m2=\frac{5-3}{1-0}=\frac{2}{1}=2$

∵ m1 = 3/2 and m2 = 2

- The two lines have different slopes and their product not equal -1

∴ The lines L1 and L2 neither parallel nor perpendicular

7 0

3 years ago