False. Rosalind Franklin, Maurice Wilkins, James Watson, and Francis Crick found out the actual structure of the DNA molecule by x-rays and research.
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What happens to the ocean water as it moves from Antarctica to the equator is : ( B ) It becomes less dense and rises to the surface.
<h3>Concept conveyor belt </h3>
The conveyor belt is a system of oceans which transports water and propel deep current of water bodies across the globe based on the differences in water densities.
As the ocean water moves from the Antarctica to the equator the cold ocean water mixes with the warm ocean water at the equator, which makes the water less dense and rises to the surface.
Hence we can conclude that What happens to the ocean water as it moves from Antarctica to the equator is It becomes less dense and rises to the surface.
Learn more about the conveyor belt : brainly.com/question/14910379
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I think it would be more like a book of blue prints because you have so much in your DNA like a book but one blue print just shows you one structure. <span />
Answer:
(i) 1 moles of C
(ii) 4.5 moles of C
Explanation:
The Chemical equation is as follow,
A + 2 B → C
This chemical equation can be translated as;
(i) 1 mole of A reacts with 2 moles of B
(ii) 1 mole of A produces 1 mole of C
(iii) 2 moles of B reacts with 1 mole of A
(iv) 2 moles of B produces 1 mole of C
(v) 1 mole of C is produced by 1 mole of A and 2 moles of B
Therefore to find the number of moles of C produced by 2 mole of B we will do following proportional method.
As,
2 moles of B produced = 1 mole of C
So,
2 moles of B will produce = X moles of C
Solving for X,
X = 2 moles × 1 mole / 2 moles
X = 1 moles of C
Note:
In above problem the given moles were the same as that present in balance equation so incase if the moles are different from that of the equation then the method shown above can be used to solve it.
Lets try it for 9 moles of B:
As,
2 moles of B produced = 1 mole of C
So,
9 moles of B will produce = X moles of C
Solving for X,
X = 9 moles × 1 mole / 2 moles
X = 4.5 moles of C