Question

Purple flowers are dominant to white flowers. A heterozygous purple flower is crossed with a white flower. What are the probabilities of the phenotypes and genotypes of their offspring?

Answer 1

Answer:

50% probability of Pp (purple) or pp (white) genotype.

Explanation:

P = purple gene

p = white gene

Punnet squares show the possible genotypes and probabilities of each genotype in the offspring of a cross:

Purple flower genotype (heterozygous) = Pp

White flower genotype = pp

Punnet Square:

$\left[\begin{array}{ccc}&P&p\\p&Pp&pp\\p&Pp&pp\end{array}\right]$

Potential genotypes for offspring are Pp and pp;

According to the Punnett square, 2 of 4 offspring will have the Pp genotype and the other 2 will have pp genotypes;

This means 2 should be purple and 2 white;

Or, there is a 50% chance of having either genotype, of being purple or white.

Answer 2

Let us assume the following:

• Flower color is represented by the allele A.
• Hence, the dominant purple color would be A, while the alternate white color would be represented by a.

From the above assumptions, a heterozygous purple flower would have the genotype Aa, while a white flower would have the genotype aa.

Now, crossing the two flowers:

       Aa    x    aa

   Aa   Aa   aa   aa

From the results of the cross, the offspring's genotypes, phenotypes, and their respective probabilities would be as follows:

• Aa - purple color - 1/2
• aa - white flower color - 1/2

In order words, the cross will yield offspring with purple color flower (genotype, Aa) and white flower color (genotype, aa) each with 1/2 probability.

More about monohybrid crossing can be found here: brainly.com/question/15521718