Answer:
a = 50t
Step-by-step explanation:
The graph goes through (0,0) so the y intercept is 0
a=5t
a=50t
a=50 + t not it
a=10t
The slope is y/x since the y intercept is 0
m = 50/1 = 50
The equation for the line is
y = 50x+0
y = 50x
Using the variables given
a = 50t
<span>Dawn was at 6 am.
Variables
a = distance from a to passing point
b = distance from b to passing point
c = speed of hiker 1
d = speed of hiker 2
x = number of hours prior to noon when dawn is
The first hiker travels for x hours to cover distance a, and the 2nd hiker then takes 9 hours to cover that same distance. This can be expressed as
a = cx = 9d
cx = 9d
x = 9d/c
The second hiker travels for x hours to cover distance b, and the 1st hiker then takes 4 hours to cover than same distance. Expressed as
b = dx = 4c
dx = 4c
x = 4c/d
We now have two expressions for x, set them equal to each other.
9d/c = 4c/d
Multiply both sides by d
9d^2/c = 4c
Divide both sides by c
9d^2/c^2 = 4
Interesting... Both sides are exact squares. Take the square root of both sides
3d/c = 2
d/c = 2/3
We now know the ratio of the speeds of the two hikers. Let's see what X is now.
x = 9d/c = 9*2/3 = 18/3 = 6
x = 4c/d = 4*3/2 = 12/2 = 6
Both expressions for x, claim x to be 6 hours. And 6 hours prior to noon is 6am.
We don't know the actual speeds of the two hikers, nor how far they actually walked. But we do know their relative speeds. And that's enough to figure out when dawn was.</span>
Answer:
AAAAAAAAAAAAAAAAAAAAAAAAAA
Step-by-step explanation:
BECAUSE IT'S AAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAA
Answer:
109410480 dates.
Step-by-step explanation:
We can find 555*888*222 different dates = 109410480 dates.
This is because we can find the total number of combinations between the different choices by multiplying the numbers of each different factor.
Hope this helped!
Approximate solutions are
X subset 2 is approximately equal to -2.72
X subset 1 is approximately equal to -0.28
