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Snowcat [4.5K]
3 years ago
8

I need help on this please

Mathematics
1 answer:
AnnZ [28]3 years ago
5 0

Answer:

Balblair! op opopopopoop

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Yoko needs 300 copies of her resume printed. Dakota printing charges 19.50$ for the first 200 copies and 9$ for every 100 additi
Leokris [45]

Answer:

A. c(r)=$19.5 if r < 2

c(r)=$19.5+(r-2) ($9) (1.045) if r ≥ 2

B. $29.78

Step-by-step explanation:

A. Based on the information given if we are to express the cost of the resumes which is c(r) algebraically as a piecewise function what we would have will be:

c(r)=$19.5 when r represent an INTERGER and is less than 2

c(r)=$19.5+(r-2) ($9) (1+0.045)

c(r)=$19.5+(r-2) ($9) (1.045) when r represent an INTERGER and is greater than 2

Therefore to express the cost of the resumes c(r) algebraically as a piecewise function will be: c(r)=$19.5 if r < 2

c(r)=$19.5+(r-2) ($9) (1.045) if r ≥ 2

B. Calculation for How much will 300 copies cost, including a sales tax of 4 1/2%

Cost of 300 copies=($19.5+$9)+($19.5+$9) (0.045)

Cost of 300 copies=$28.5+$28.5(0.045)

Cost of 300 copies=$28.50+$1.28

Cost of 300 copies=$29.78

Therefore How much will 300 copies cost, including a sales tax of 4 1/2% will be $29.78

7 0
3 years ago
What is the energy of a photon of orange light with a frequency of 4.84 x 1014 Hz?
cestrela7 [59]
I don’t understand your question can you go into more detail please
8 0
2 years ago
3x+6/x^2-x-6+2x/x^2+x-12
Tanzania [10]
\dfrac{3x+6}{x^2-x-6} +  \dfrac{2x}{x^2+x-12}

= \dfrac{3(x+2)}{(x + 2)(x - 3)} +  \dfrac{2x}{ (x - 3)(x + 4)}

= \dfrac{3}{(x - 3)} +  \dfrac{2x}{ (x -3)(x + 4)}

= \dfrac{3(x+4)}{(x - 3)(x + 4)} +  \dfrac{2x}{ (x -3 )(x + 4)}

= \dfrac{3(x+4) + 2x }{(x - 3)(x + 4)}

= \dfrac{3x+12 + 2x }{(x - 3)(x + 4)}

= \dfrac{5x+12}{(x - 3)(x + 4)}



6 0
3 years ago
The weight of an object on Venus is approximately 9/10 of its weight on Earth. The weight of an object
Sergeeva-Olga [200]

An object weighs 140 pounds more on Jupiter than it weighs on Venus. By simple algebraic operations, the required value is calculated.

<h3>What are the algebraic operations?</h3>

Addition, subtraction, multiplication, and division are the basic algebraic operations that are used for many computations.

<h3>Calculation:</h3>

It is given that,

An object's weight on Venus is approximately 9/10 of its weight on earth. I.e., WV = 9/10 WE

An object's weight on Jupiter is approximately 23/10 of its weight on earth. I.e., WJ = 23/10 WE

If an object weighs 100 pounds on earth, then

The weight of the object on Venus is

WV = 9/10 × 100 = 90 pounds

The weight of the object on Jupiter is

WJ = 23/10 × 100 = 230

Thus, the difference between them is 230 - 90 = 140 pounds.

So, the object weighs 140 pounds more on Jupiter than on Venus.

Learn more about algebraic operations here:

brainly.com/question/24935016

#SPJ4

8 0
1 year ago
Algebra applications: find the value of x and y​
Inga [223]

Answer : The value of x and y is 8 and 10 respectively.

Step-by-step explanation :

As we known that if two parallel lines are cut by a transversal line then consecutive interior angles are supplementary.

From the given figure we conclude that:

5x-y+150=180       ...........(1)

5x-y=180-150

5x-y=30      ............(2)

5x+y+130=180       ...........(3)

5x+y=180-130

5x+y=50        ...........(4)

Now we adding equation 2 and 4, we get the value of x.

5x-y+5x+y=30+50

10x=80

x=8

Now we are putting the value of x in 4, we get the value of y.

5x+y=50

5(8)+y=50

y=50-40

y=10

Therefore, the value of x and y is 8 and 10 respectively.

3 0
3 years ago
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