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I am Lyosha [343]
3 years ago
5

Find the difference of 3/4 and 1/28.

Mathematics
2 answers:
adell [148]3 years ago
4 0

3/4 = 21/28 after multiplying top and bottom of 3/4 by the value 7

3*7 = 21 and 4*7 = 28

The goal is to get 3/4 into an equivalent fraction that has 28 as the denominator.

------------------------------------

So 3/4 - 1/28 is the same as 21/28 - 1/28

The denominators are the same. We subtract the numerators to get 21-1 = 20. The denominators stay the same at 28

We have

21/28 - 1/28 = (21-1)/28 = 20/28

Now reduce 20/28 as much as possible. Divide both parts by the GCF 4

20/4 = 5

28/4 = 7

The final answer is 5/7

Zepler [3.9K]3 years ago
3 0

Answer:

That would be the first option-  5/7

Step-by-step explanation:

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State the domain, the range, and the intervals on which function is increasing, decreasing, or constant in interval notation
aleksandr82 [10.1K]

Answer:

Domain: [-1,\infty)

Range: (-\infty, 3]

Decreases over: (-1,-\infty)

Step-by-step explanation:

Given

f(x) = -\sqrt{x + 1} + 3 --- Missing from the question

Solving (a): The domain

To get the domain, the expression under the square root must not be negative.

In other words:

x + 1 \ge 0

Solve for x

x + 1 -1\ge 0-1

x \ge -1

Hence, the domain is:

[-1,\infty)

To get the range, we plot the values of the domain in the expression.

x = -1

f(x) = -\sqrt{x + 1} + 3

f(-1) = -\sqrt{-1+1} +3

f(-1) = -\sqrt{0} +3

f(-1) = -0 +3

f(-1) = 3

x = \infty

f(\infty) = -\sqrt{\infty +1}+3

f(\infty) = -\sqrt{\infty}+3

f(\infty) = -\infty+3

f(\infty) = -\infty

So, the range is: (-\infty, 3]

To get the interval where the function increases or not, we simply plot the graph of f(x).

See attachment for graph.

From the attachment, it will be observed that the graph of f(x) continuously decreases from x = -1, and it never increased.

This implies that, the graph decreases over the interval (-1,-\infty)

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Answer:

d> -7

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