In general, the average rate of change of f (x) on the interval a, b is given by f(b) – f(a) / b – a. The average rate of alteration of a function, f (x) on an interval is well-defined to be the variance of the function values at the endpoints of the interim divided by the difference in the x values at the endpoints of the interval. this is also known as the difference quotient that tells how on average, the y values of a function are changing in connection to variations in the x values. A positive or negative rate of change is applicable which match up to an increase or decrease in the y value among the two data points. It is called zero rate of change when a quantity does not change over time.
Answer:
- B) One solution
- The solution is (2, -2)
- The graph is below.
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Explanation:
I used GeoGebra to graph the two lines. Desmos is another free tool you can use. There are other graphing calculators out there to choose from as well.
Once you have the two lines graphed, notice that they cross at (2, -2) which is where the solution is located. This point is on both lines, so it satisfies both equations simultaneously. There's only one such intersection point, so there's only one solution.
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To graph these equations by hand, plug in various x values to find corresponding y values. For instance, if you plugged in x = 0 into the first equation, then,
y = (-3/2)x+1
y = (-3/2)*0+1
y = 1
The point (0,1) is on the first line. The point (2,-2) is also on this line. Draw a straight line through the two points to finish that equation. The other equation is handled in a similar fashion.
8-4x^2+10x^2+2x
8+6x^2+2x
6x^2+2x+8
This is a quadratic equation since it has three terms. Now, a=6 (that is, a≠0) and therefore, it is a quadratic trinomial equation.
The correct answer is C.)
Answer:
864 ft^2.
Step-by-step explanation:
Area of the base = 16^2 = 256.
Area of the triangular sides = 4 * 1/2 * 16 * 19
Total area = 256 + 608
= 864 ft^2.
The answer is B)0.4 because four of the ten stores that were surveyed were compliant so the proportion of the entire population of stores that would be compliant is <span>410</span> or 0.4<span>
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