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amm1812
3 years ago
13

Find the values that make this a parallelogram (please show work)

Mathematics
1 answer:
Dmitry [639]3 years ago
7 0

Answer:

Correct answer is: 7. y = 28° and x = 29°   8. y = 7 and x = 5

Step-by-step explanation:

7.

In the parallelogram, adjacent angles are supplementary and the opposite angles are the same.

According to this:

(3 y - 20) + (4 y + 4) = 180 => 7 y - 16 = 180 => 7 y = 180 + 16 => 7 y = 196

y = 196/7 = 28°  =>  y = 28°

4 x + (2 x + 6) = 180 => 6 x + 6 = 180 => 6 x = 180 - 6 => 6 x = 174

x = 174/6 = 29°  => x = 29°

8.

At the parallelogram, the diagonal is split into two equal parts.

According to this:

3 y - 3 = 2 y + 4 => 3 y - 2 y = 4 + 3 => y = 7

x - 1 = 2 x - 6 => 2 x - x = 6 - 1 => x = 5

God with you!!!

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<u>It should be -1.16</u>

Step-by-step explanation:

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Finger [1]

Answer:

x= 9

Step-by-step explanation:

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What sequence begins with the number five and then adds five each time?
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3 years ago
Find the simple interest on a $340 loan at a 15% annual interest rate for 1<br> year
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Answer:

$51.

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4 0
3 years ago
Read 2 more answers
I need help 6x-2y=10 x-2y=-5 solve by elimination
dem82 [27]
<h3><u>Explanation</u></h3>
  • Given the system of equations.

\begin{cases} 6x - 2y = 10 \\ x - 2y =  - 5 \end{cases}

  • Solve the system of equations by eliminating either x-term or y-term. We will eliminate the y-term as it is faster to solve the equation.

To eliminate the y-term, we have to multiply the negative in either the first or second equation so we can get rid of the y-term. I will multiply negative in the second equation.

\begin{cases} 6x - 2y = 10 \\  - x  +  2y =  5 \end{cases}

There as we can get rid of the y-term by adding both equations.

(6x - x) + ( - 2y + 2y) = 10 + 5 \\ 5x + 0 = 15 \\ 5x = 15 \\ x =  \frac{15}{5}  \longrightarrow  \frac{ \cancel{15}}{ \cancel{5}}  =  \frac{3}{1}  \\ x = 3

Hence, the value of x is 3. But we are not finished yet because we need to find the value of y as well. Therefore, we substitute the value of x in any given equations. I will substitute the value of x in the second equation.

x - 2y =  - 5 \\ 3 - 2y =  - 5 \\ 3 + 5 = 2y \\ 8 = 2y \\  \frac{8}{2}  = y \\ y =  \frac{8}{2} \longrightarrow  \frac{ \cancel{8}}{ \cancel{2}}  =  \frac{4}{1}  \\ y = 4

Hence, the value of y is 4. Therefore, we can say that when x = 3, y = 4.

  • Answer Check by substituting both x and y values in both equations.

<u>First</u><u> </u><u>Equation</u>

6x - 2y = 10 \\ 6(3) - 2(4) = 10 \\ 18 - 8 = 10 \\ 10  = 10 \longrightarrow \sf{true} \:  \green{ \checkmark}

<u>Second</u><u> </u><u>Equation</u>

x - 2y =  - 5 \\ 3 - 2(4) =  - 5 \\ 3 - 8 =  - 5 \\  - 5 =  - 5 \longrightarrow  \sf{true} \:  \green{ \checkmark}

Hence, both equations are true for x = 3 and y = 4. Therefore, the solution is (3,4)

<h3><u>Answer</u></h3>

\begin{cases} x = 3 \\ y = 4 \end{cases} \\  \sf \underline{Coordinate \:  \: Form} \\ (3,4)

8 0
3 years ago
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