Question

The graph of y=h(x)y=h(x)y, equals, h, left parenthesis, x, right parenthesis is a line segment joining the points (1,9)(1,9)left parenthesis, 1, comma, 9, right parenthesis and (3,2)(3,2)left parenthesis, 3, comma, 2, right parenthesis. Drag the endpoints of the segment below to graph y=h^{-1}(x)y=h −1 (x)y, equals, h, start superscript, minus, 1, end superscript, left parenthesis, x, right parenthesis.

Answer 1

Answer:

End points of the this segment are (9,1) and (2,3).

Step-by-step explanation:

The given function is

$y=h(x)$

End points of the this segment are (1,9) and (3,2).

If a function is defined as

$f=\{(a,b),a\in R,b\in R\}$ then

$f^{-1}=\{(b,a),a\in R,b\in R\}$

It means, we have to interchange x and y-coordinates of the end points.

So, end points of the this segment are (9,1) and (2,3).

Plot these point and join them by a line segment.

Answer 2

Answer:

(−6,7) and (-1,-2) on khan

Step-by-step explanation:

i checked it