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VLD [36.1K]
3 years ago
8

Find the indicated side of the right triangle

Mathematics
2 answers:
Tcecarenko [31]3 years ago
7 0

Answer:

\tan(30)  =  \frac{7}{x}

\frac{1}{ \sqrt{3} }  =  \frac{7}{x}

x = 7 \sqrt{3}

Black_prince [1.1K]3 years ago
4 0

Answer:

7 * sqrt(3) =x

Step-by-step explanation:

Since this is a right triangle, we can use trig functions

tan theta = opp/ adj

tan 60 = x/7

Multiply each side by 7

7 tan 60 =x

We know than 60 =sqrt(3)

7 * sqrt(3) =x

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X-4[x-2(x+6)]=5x+3<br><img src="https://tex.z-dn.net/?f=x%20-%204%20%20%20%5B%20%20x%20-%202%28x%20%2B%206%29%5D%20%20%3D%205x%2
pshichka [43]

The equivalence of the equation is 5x + 48 = 5x + 3.

Since 48 cannot be equal to 3, hence there are no solution.

<h3>What is the value of x?</h3>

Given the equation; x-4[ x - 2( x + 6) ] = 5x + 3

We remove the parentheses

x-4[ x - 2( x + 6) ] = 5x + 3

x-4[ x - 2x - 12 ] = 5x + 3

x - 4x + 8x + 48 = 5x + 3

5x + 48 = 5x + 3

We can go further and collect like terms

5x - 5x + 48 = 3

48 ≠ 3

Since 48 cannot be equal to 3, hence there are no solution.

Learn more about equations here: brainly.com/question/14686792

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7 0
2 years ago
Three numbers X, Y, and Z are in the ratio 2:7:8. If 12 is subtracted from Y, then three numbers form a geometric sequence (in t
Dimas [21]
A geometric sequence is a sequence in which there is a common ratio between any two consecutive terms. In this case if X:Y:Z are in the ratio of 2:7:8 the multiplying by a constant k, we have X=2k, Y= 7k and Z=8k.
Then if  X, Y-12, Z form a Geometric sequence, it means X/Y-12=Y-12/Z which is the same as 2k/7k-12=7k-12/8k if we cross multply, we get
   16k²= 49k²-168k +144
  33k²-168k+144 =0 solving for k
k = 4 or 1.091 if we take the whole number  to find the values of X,Y and z,
X= 8, Y= 28 and Z=32 
3 0
3 years ago
Which ordered pair is a solution of the system of a linear equation below? Y= 1/4x +2 y= x-1
Tanya [424]

Answer:  x = 4, y = 3

<u>Step-by-step explanation:</u>

y=\dfrac{1}{4}x+2    and      y=x-1

Using substitution method we get:

x-1=\dfrac{1}{4}x+2\\\\\text{subtract}\ \dfrac{1}{4}x\ \text{from both sides}\rightarrow \dfrac{3}{4}x-1=2\\\\\text{add 1 to both sides}\rightarrow \dfrac{3}{4}x=3\\\\\text{multiply both sides by 4}\rightarrow 3x=12\\\\\text{divide both sides by 3}\rightarrow x=4\\\\\text{Insert x = 4 into one of the original equations to solve for y:}\\y=x-1\\y =(4)-1\\y=3

3 0
3 years ago
Classify △ABC
tensa zangetsu [6.8K]

Answer:

b and d

Step-by-step explanation:

4 0
3 years ago
Absolute value of -4 1/2
iragen [17]

Answer: 4 1/2

Step-by-step explanation:

4 0
3 years ago
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