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yKpoI14uk [10]
4 years ago
11

What is the sum of the first six terms of the geometric series? 2 – 6 + 18 – 54 + ...

Mathematics
2 answers:
Arte-miy333 [17]4 years ago
5 0

Answer:

The answer is B (-364)

Step-by-step explanation:

weeeeeb [17]4 years ago
4 0

Answer:

-364

Step-by-step explanation:

Each number is being multiplied by -3

2 , -6 , 18 , -54 , 162 , -486

Add them all up

-364

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Which equation is quadratic in form?
iren2701 [21]
2(x+5)2+8x+5+6=0 is the answer
8 0
3 years ago
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168% of what number is 714 and how do you get the answer??
DerKrebs [107]

Answer:

1199.52

Step-by-step explanation:

714/x=100/168

(714/x)*x=(100/168)*x       - we multiply both sides of the equation by x

714=0.5952380952381*x       - we divide both sides of the equation by (0.5952380952381) to get x

714/0.5952380952381=x

1199.52=x

x=1199.52

4 0
3 years ago
Find the midpoint of the segment with the given endpoints ​(-​5,-9​) and ​(​-9,-3​)
meriva

Answer:

(-7,-6)

Step-by-step explanation:

x =  \frac{ -5 - 9}{2}  =   - 7 \\  \\ y =  \frac{  - 9 - 3}{2}  =  - 6 \\

7 0
3 years ago
What are two different strategies for finding the product of 472 and 33.
Bad White [126]
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4 0
3 years ago
In order to conduct an experiment, 4 subjects are randomly selected from a group of 20 subjects. How many different groups of fo
irga5000 [103]

Answer:

The number of ways to form different groups of four subjects is 4845.

Step-by-step explanation:

In mathematics, the procedure to select k items from n distinct items, without replacement, is known as combinations.

The formula to compute the combinations of k items from n is given by the formula:

{n\choose k}=\frac{n!}{k!\times (n-k)!}

In this case, 4 subjects are randomly selected from a group of 20 subjects.

Compute the number of ways to form different groups of four subjects as follows:

{n\choose k}=\frac{n!}{k!\times (n-k)!}

{20\choose 4}=\frac{20!}{4!\times (20-4)!}

      =\frac{20\times 19\times 18\times 17\times 16!}{4!\times 16!}\\\\=\frac{20\times 19\times 18\times 17}{4\times3\times 2\times 1}\\\\=4845

Thus, the number of ways to form different groups of four subjects is 4845.

5 0
3 years ago
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