Answer:
1. Determine the genotypes of the parents.
2. Determine which genes are recessive and which are dominant.
3. Create a Punnett square for all the possibilities.
4. List the all possible genotypes and phenotypes for the couple's offspring.
Explanation:
It's a way of protecting the trees, and making sure they survive the winter and beyond. Leaves die during the winter months. If those dead leaves stayed on the trees, and new ones wouldn't grow in their place, the tree would have no way of making food for themselves.
Hope it helps. ☺
Answer:
- Parental cross = Cch x chch
- F1 = 1/2 Cch (agouti coat); 1/2 chch (albino coat) >> 1:1 phenotypic ratio
Punnett square:
ch ch
C Cch Cch
ch chch chch
Explanation:
A heterozygous individual is an individual who has two different gene variants (i.e., alleles) at a particular <em>locus</em>. In this case, individuals having the "agouti coat" trait are heterozygous carrying both 'C' and 'ch' alleles. On the other hand, a homo-zygous individual has the same allele at a given <em>locus</em> (here, the 'chch' genotype associated with the albino phenotype). Therefore, as observed in the Punnett Square above, when a heterozygous parent is crossed with a homo-zygous recessive parent for a single gene, alleles segregate in the gametes of both parents so an expected 1:1 phenotypic ratio will be observed.
Answer:
Read Below
Explanation:
Nucleotides are A & T and G&C you see in DNA and in RNA T is Replaced by U. The reason they must be balanced between G&C and T&A is because G has to bond with A in DNA and G with C so if there is more G than C that means there is mismatches between the DNA nucleotides same thing for A and T. In RNA you follow the same rule. If we have lets say 27% of our DNA as A we have to have 27% as T leaving 23% as C and 23% as G. If there was lets say 29% T while one 27% A then there was a error in DNA replication and could lead to errors in RNA synthesis if not corrected
