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zysi [14]
3 years ago
8

Delaney would like to make a 5 lb nut mixture that is 60% peanuts and 40% almonds. She has several pounds of peanuts and several

pounds of a mixture that is 20% peanuts and 80% almonds. Let p represent the number of pounds of peanuts needed to make the new mixture, and let m represent the number of pounds of the 80% almond-20% peanut mixture.
(a) What is the system that models this situation?
(b) Which of the following is a solution to the system: 2 lb peanuts and 3 lb mixture; 2.5 lb peanuts and 2.5 lb mixture; 4 lb peanuts and 1 lb mixture? Show your work.
Mathematics
1 answer:
jonny [76]3 years ago
4 0

A) A ratio system

B) The 4 lb peanuts and the 1 lb mixture because the 4lb added to the 1lb of mixture give the correct percentages.

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Answer:

Step-by-step explanation:

Independent Variable

The independent variable is the condition that you change in an experiment. It is the variable you control. It is called independent because its value does not depend on and is not affected by the state of any other variable in the experiment. Sometimes you may hear this variable called the "controlled variable" because it is the one that is changed. Do not confuse it with a "control variable," which is a variable that is purposely held constant so that it can't affect the outcome of the experiment.

Dependent Variable

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A speck of dust in an electron microscope is 1.2x10^2 millimeters wide. The image is 5x10^2 times larger than the actual size. H
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4 years ago
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Need help with equations with variables on both sides, giving 100 points, tysm if you help :) 6 (2x-4) = 8(x +2) A. 3 B. 10 C. 2
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B. 10

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Step-by-step explanation:

6 (2x-4) = 8(x + 2)

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Subtract both sides by '8x'

12x - 8x - 24 = 8x - 8x + 16

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3(4p - 2) = -6(1 - 2p)

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0 - 6 + 6 = -6 + 6

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