1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
rodikova [14]
3 years ago
7

Standard form? Help plz

Mathematics
1 answer:
prisoha [69]3 years ago
3 0
The answer is 5x + 76y
There is no complete standard form because there is no value for x or y given.
You might be interested in
I need the answers to these or for someone to tell me how to figure it out
Lorico [155]

Answer:

4. Scalene

5. Isosceles

6. Isosceles

7. Equilateral

8. Right

9. Scalene

4 0
3 years ago
Read 2 more answers
The distance traveled, in feet, of a ball dropped from a tall building is modeled by the equation d(t) = 16t2 where d equals the
ohaa [14]

Answer:

A.48

Step-by-step 789333

6 0
3 years ago
Suppose a basketball player has made 231 out of 361 free throws. If the player makes the next 2 free throws, I will pay you $31.
statuscvo [17]

Answer:

The expected value of the proposition is of -0.29.

Step-by-step explanation:

For each free throw, there are only two possible outcomes. Either the player will make it, or he will miss it. The probability of a player making a free throw is independent of any other free throw, which means that the binomial probability distribution is used to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

Suppose a basketball player has made 231 out of 361 free throws.

This means that p = \frac{231}{361} = 0.6399

Probability of the player making the next 2 free throws:

This is P(X = 2) when n = 2. So

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 2) = C_{2,2}.(0.6399)^{2}.(0.3601)^{0} = 0.4095

Find the expected value of the proposition:

0.4095 probability of you paying $31(losing $31), which is when the player makes the next 2 free throws.

1 - 0.4059 = 0.5905 probability of you being paid $21(earning $21), which is when the player does not make the next 2 free throws. So

E = -31*0.4095 + 21*0.5905 = -0.29

The expected value of the proposition is of -0.29.

3 0
2 years ago
2(5n - 2 ) = 4 ( n + 2 )
Marianna [84]
2(5n-2)=4(n+2)
10n-4=4n+8
6n-4=8
6n=12
n=2
3 0
3 years ago
Read 2 more answers
a foreman must order enough sod to cover a dirt area 36 feet wide by 28 feet long. each piece of sod is 3 feet long and 12 inche
Andrews [41]

If we divide the area we have to cover by the area of a piece, we will get the number of pieces needed:

n=\dfrac{\text{dirt area}}{\text{piece area}}=\dfrac{36\times 28}{3\times 12} = \dfrac{36\times 28}{36}=28

3 0
3 years ago
Other questions:
  • 1. f(x) = x(x-6)(x+3)
    7·1 answer
  • Calculate.<br> 1) 4 x (3 divided by 8 + 1)
    14·1 answer
  • Is it necessary to do all of the calculations to determine the sign of the product?
    15·1 answer
  • Which is warmer -13c or -10
    7·1 answer
  • The company is building a scale model of the theater’s main show tank for an investor's presentation. Each dimension will be mad
    13·1 answer
  • WILL GIVE BRAINLY!!! PLEASE HEKP ME!!!!
    12·1 answer
  • What is the Interquartile Range (IQR) of the pumpkin weights? <br> a) 10<br> b) 4<br> c) 15<br> d) 8
    7·2 answers
  • William has 24 cans of fruit and 60 cans of vegetables that he will be putting into bags for a food drive. He wants each bag to
    8·1 answer
  • A baby giraffe eats 75 pounds of leaves a day. How many pounds of leaves does a baby giraffe eat in 31 days? explain your reason
    7·2 answers
  • Find f(-2) for f(x) = 3x2^x
    12·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!