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Varvara68 [4.7K]
3 years ago
9

Special right triangles, find x and y

Mathematics
1 answer:
egoroff_w [7]3 years ago
5 0

Answer:

The answer to your question is x = 17.32; y = 8.67

Step-by-step explanation:

Process

1.- Use trigonometric functions to find x and y

   a) sin Ф = \frac{opposite side}{hypotenuse}

      Ф = 60°

      opposite side = 15

      hypotenuse = ?

     hypotenuse = \frac{opposite side}{sin \alpha }

     hypotenuse = \frac{15}{sin 60}

     hypotenuse = \frac{15}{0.87}

            hypotenuse = 17.32

     b) cosФ = \frac{y}{hypotenuse}

         y = hypotenuse x cos 60

         y = 17.32 x 0.5

                y = 8.67

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5 0
3 years ago
Oranges are packaged in containers oranges are packaged and seven containers
Marrrta [24]

Answer:

your question is unclear but if i were to guess you should multiply 7 with the amount of oranges in a container to get the total

Step-by-step explanation:

3 0
3 years ago
Determine whether the set of vectors is a basis for ℛ3. Given the set of vectors , decide which of the following statements is t
schepotkina [342]

Answer:

(A) Set A is linearly independent and spans R^3. Set is a basis for R^3.

Step-by-Step Explanation

<u>Definition (Linear Independence)</u>

A set of vectors is said to be linearly independent if at least one of the vectors can be written as a linear combination of the others. The identity matrix is linearly independent.

<u>Definition (Span of a Set of Vectors)</u>

The Span of a set of vectors is the set of all linear combinations of the vectors.

<u>Definition (A Basis of a Subspace).</u>

A subset B of a vector space V is called a basis if: (1)B is linearly independent, and; (2) B is a spanning set of V.

Given the set of vectors  A= \left(\begin{array}{[c][c][c][c]}1 & 0 & 0 & 0\\ 0 & 1 & 0 & 1\\ 0 & 0 & 1 & 1\end{array} \right) , we are to decide which of the given statements is true:

In Matrix A= \left(\begin{array}{[c][c][c][c]}(1) & 0 & 0 & 0\\ 0 & (1) & 0 & 1\\ 0 & 0 & (1) & 1\end{array} \right) , the circled numbers are the pivots. There are 3 pivots in this case. By the theorem that The Row Rank=Column Rank of a Matrix, the column rank of A is 3. Thus there are 3 linearly independent columns of A and one linearly dependent column. R^3 has a dimension of 3, thus any 3 linearly independent vectors will span it. We conclude thus that the columns of A spans R^3.

Therefore Set A is linearly independent and spans R^3. Thus it is basis for R^3.

8 0
3 years ago
A) If the 5th term of an A.P. is double the 7th term, show that the sum of the 17 terms zero.​
gayaneshka [121]

Answer:

see explanation

Step-by-step explanation:

The nth term of an AP is

a_{n} = a₁ + (n - 1)d

where a₁ is the first term and d the common difference

Given a₅ is double a₇ , then

a₁ + 4d = 2(a₁ + 6d) , that is

a₁ + 4d = 2a₁ + 12d ( subtract a₁ from both sides )

4d = a₁ + 12d ( subtract 12d from both sides )

- 8d = a₁

The sum of n terms of an AP is

S_{n} = \frac{n}{2} [ 2a₁ + (n - 1)d ] , substitute values

S_{17} = \frac{17}{2} ( 2(- 8d) + 16d)

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5 0
2 years ago
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jek_recluse [69]

Answer:

y = 2/7 x - 51/7

Step-by-step explanation:

Equation of the line

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(y-(-7)/(-9-(-7) = (x-1)/(-6-1)

(y+7)/-2 = (x-1)/-7

(-y-7)/2 = (-x+1)/7

-y-7 = -2/7 x + 2/7

-y = -2/7x +2/7 + 7

y = 2/7 x - 2/7 - 7

y = 2/7 x + (-2-49)/7

y = 2/7 x - 51/7

3 0
3 years ago
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