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balu736 [363]
3 years ago
14

At 4 p.m., the temperature started to change drastically. Each hour, for three hours, the temperature decreased by 7°F. Which ex

pression best shows another way to write the product for the temperature change?
Mathematics
2 answers:
attashe74 [19]3 years ago
6 0

Answer:

The correct option is A

Step-by-step explanation:

The question is incomplete because the options are not given for the question. Lets complete the question first. The options for this question are given below.

A)   (-1)(7+7+7)

B)   (-7)+(-7)+(-7)+(-7)

C)   7+7+7

D)   7+7+7+7

Now look at the conditions given. Supoose at 4pm, the temperature is x°F at 4pm. As temperature is decreasing 7°F every hours, and it happenss for 4 hours.

We can say that after one hour, temperature is:

5pm: x°F - 7°F

After two hours:

6pm: x°F - 7°F - 7°F

After three hours:

7pm: x°F - 7°F - 7°F - 7°F

Hence, the expression is given by:

-7 - 7 - 7

or

(-1)(7+7+7)

Ronch [10]3 years ago
5 0

Answer:

(-1)(7+7+7)

Step-by-step explanation:

I got it right on the test

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<B = <G

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ABC ≅FGH

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Finding the quotient of this answer
Mekhanik [1.2K]
30/36 or 5/6 because to divide by a fraction, you multiply by its reciprocal.To find the reciprocal of a fraction you can simply just flip the fraction so 6 / (5/6) is equal to 6*(5/6).This is equal to (6*5)/(6*6) or 30/36 or 5/6.
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3 years ago
Mister Rogers is fencing another new rectangular garden in his neighborhood. One side of the garden faces the road and needs to
Oksanka [162]

Answer:

length of the pretty side  and length of the side oppositte to the pretty side  =   37.91 ft

length of the other two sides  = 27.52 ft

Step-by-step explanation:

The mathematical problem is:

Max A = b1*h

subject to: 35*b1 + 18*(2*h + b2) <= 3000

Where

A: area of the garden

b1: length of the pretty side

b2: length of the side oppositte to the pretty side

h: length of the other two sides

Replacing with b1 = b2 and taking only the equality sign in the restriction (in the maximum all the money will be spent), we get:

35*b1 + 18*(2*h + b1) = 3000

35*b1 + 36*h + 18*b1 = 3000

53*b1 + 36*h = 3000

b1 = 3000/53 - (36/53)*h

Substituing in Area's formula  

A = (3000/53 - (36/53)*h)*h

A = (3000/53)*h - (36/53)*h^2

In the maximum, the derivative of A is equal to zero

dA/dh = 3000/53 - 2*(36/53)*h =

3000/53 - 72/35*h = 0

h = (3000/53)*(35/72)

h = 27.52 ft

then,

b1 = 3000/53 - (36/53)*27.52

b1 = 37.91 ft =b2

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Answer:

5 m/s

Step-by-step explanation:

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