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musickatia [10]
3 years ago
15

Marci has45 red buttns and 60 yellow butto a she wants to use all of the butt s a d divide each color equally into boxes what is

the greatest number of boxes marci can use to divide the buttons
Mathematics
1 answer:
aksik [14]3 years ago
5 0
7 because 45+60=105÷7=15
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Can someone please help me with these two please I'll appreciate it :)
s344n2d4d5 [400]
4.

\sqrt{64}=8\\\\8\dfrac17=8.14285714...\\\\8.\overline{14}=8.14141414...\\\\ \dfrac{15}2=7,5\\\\\\ \boxed{\ \dfrac{15}2\ \ \textless \ \ \sqrt{64}\ \ \textless \ \ 8.\overline{14}\ \ \textless \ \ 8\dfrac17\ }

5.

\sqrt{18}  doesn't belong with the other three because it is irrational number
The other three can be expressed as a ratio between two <span>integers.

-\dfrac{10}2=\dfrac{-10\ }2\\\\-13.4=-13\frac4{10}=\frac{-134}{\ 10}\\\\ 22.\overline7=22\frac79=\frac{205}9\\\\\\ \sqrt{18}=\sqrt{9\cdot2}=\sqrt9\cdot\sqrt2=3\sqrt2
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7 0
3 years ago
the area of a triangle is 124 square units. what would it's new area be if its base was half as long and its height was three ti
Montano1993 [528]
To solve this problem you must apply the proccedure shown below:

 1. You have that the formula for calculate the area of a triangle is:

 A=bh/2

 Where A is the area of the triangle, b is the base of the triangle and h is the height of the triangle.

 bh/2=124
 bh=124x2
 bh=248

 2. The problem asks for the new area of the triangle <span>if its base was half as long and its height was three times as long. Then, you have:

 Base=b/2
 Height=3h

 3. Therefore, when you substitute this into the formula for calculate the area of a triangle, you obtain:

 A'=bh/2

 (A' is the new area)

 A'=(b/2)(3)/2
 A'=3bh/4

 4. When you substitute bh=248 into </span>A'=3bh/4, you obtain:
<span>
 A'=186 units</span>²
<span>
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3 0
3 years ago
Identify the factors of the function y = 6x2 – 9x
Sindrei [870]

Answer:

3x(2x - 3)

Step-by-step explanation:

Given

y = 6x² - 9x ← factor out 3x from each term

  = 3x(2x - 3)

6 0
3 years ago
Help i will give 20 points<br> And brainlist
marysya [2.9K]

Answer:

for #14, x=10

Step-by-step explanation:

in the graph, 6x = 5x +10 so if x was 10 it would be 60 = 60 so x = 10

5 0
3 years ago
Look at the picture<br>​
Sonbull [250]

\large\displaystyle\text{$\begin{gathered}\sf 9|x-8| < 36 \end{gathered}$}

\large\displaystyle\text{$\begin{gathered}\sf Divide \ both \ sides \ by \ 9. \end{gathered}$}

  • \large\displaystyle\text{$\begin{gathered}\sf  \frac{9(|x-8|)}{9} < \frac{36}{9}   \end{gathered}$}
  • \large\displaystyle\text{$\begin{gathered}\sf |x-8| < 4 \end{gathered}$}

\large\displaystyle\text{$\begin{gathered}\sf Solve \ Absolute \ Value. \end{gathered}$}

  • \large\displaystyle\text{$\begin{gathered}\sf |x-8| < 4 \end{gathered}$}

\large\displaystyle\text{$\begin{gathered}\sf We \ know \ x-8 < 4 \ and \ x-8 > -4 \end{gathered}$}

<u>                                                                                                                             </u>

         \large\displaystyle\text{$\begin{gathered}\sf x-8 < 4 \ (Condition \ 1) \end{gathered}$}\\\large\displaystyle\text{$\begin{gathered}\sf x-8+8 < 4+8 \ (Add \ 8 \ to \ both \ sides) \end{gathered}$}\\\large\displaystyle\text{$\begin{gathered}\sf x < 12 \end{gathered}$}

<u>                                                                                                                             </u>

           \large\displaystyle\text{$\begin{gathered}\sf x-8 > -4 \ (Condition \ 2) \end{gathered}$}\\\large\displaystyle\text{$\begin{gathered}\sf x-8+8 > -4+8 \ (Add \ 8 \ to \ both \ \ sides) \end{gathered}$}\\\large\displaystyle\text{$\begin{gathered}\sf x > 4 \end{gathered}$}

<u>                                                                                                                             </u>

<u />\underline{\boldsymbol{\sf{Answer}}}

\boxed{\large\displaystyle\text{$\begin{gathered}\sf x < 12 \ and \ x > 4 \end{gathered}$} }

\large\displaystyle\text{$\begin{gathered}\sf Therefore,\bf{\underline{the \  correct \ option}} \  \end{gathered}$}\large\displaystyle\text{$\begin{gathered}\sf is \ \bf{\underline{"A"}}. \end{gathered}$}

6 0
2 years ago
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