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3 years ago

Place the indicated product in the proper location on the grid 3a^2-2a^3

Mathematics

1 answer:

Solnce55 [7]3 years ago

8 0

The answer is a^2(3-2a)

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Solve for the value of z: 90/15 = 6/z

lara31 [8.8K]

Answer:

z = 1

Step-by-step explanation:

90/15 = 6/z

Cross Multiply

15 * 6 = 90 * z

90 = 90z

Divide both sides of the equation by 90

z = 1

Hope this was useful to you!

3 0

3 years ago

Please help me with theses 4 questions

MA_775_DIABLO [31]

1. 864 mm^3
2.1640 cm^3
3. 4.0 cm
4. 150pi ft^3

3 0

3 years ago

Evaluate 2x + 1 when x = 7.

Tatiana [17]

Answer:

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

zmey [24]

Answer:

Part 1) The inequality that represent this situation is $5(x+7)^{2} \geq1,050$ or $5x^{2}+70x+245 \geq1,050$

Part 2) Yes, 8 inches is a reasonable width for his tablet

Step-by-step explanation:

Part 1)

Let

L -----> the length of the screen television

W ----> the width of the screen television

x ----> the width of Andrew's tablet

we know that

$L=5W$ ------> equation A

$W=x+7$ ----> equation B

The area of the television is

$A=LW$ -----> equation C

Substitute equation A and equation B in equation C

$A=5(x+7)(x+7)$

$A=5(x+7)^{2}$

$5(x+7)^{2} \geq1,050$

$5(x^{2}+14x+49) \geq1,050$

$5x^{2}+70x+245 \geq1,050$ ------> inequality that represent this situation

Part 2) Determine if 8 inches is a reasonable width for his tablet

For x=8 in

Substitute in the inequality

$5(8+7)^{2} \geq1,050$

$5(15)^{2} \geq1,050$

$1,125 \geq1,050$ -----> is true

therefore

Yes, 8 inches is a reasonable width for his tablet

3 0

3 years ago

$70 plus a 5% tax and a 15% tip

Serjik [45]

Answer:

maybe 88.5

Step-by-step explanation:

calculator is god

5 0

3 years ago