Answer:
Ok, as i understand it:
for a point P = (x, y)
The values of x and y can be randomly chosen from the set {1, 2, ..., 10}
We want to find the probability that the point P lies on the second quadrant:
First, what type of points are located in the second quadrant?
We should have a value negative for x, and positive for y.
But in our set; {1, 2, ..., 10}, we have only positive values.
So x can not be negative, this means that the point can never be on the second quadrant.
So the probability is 0.
THE 147TH TERM IS C
I MULTIPLY 37 TO 4 WHICH IS EQUAL TO 148 WHICH IS D
SO 148 - 1 = 147 WHICH IS C
Answer: A'(-10, -4) and C''(-6, -8) B. A'(-10, -4) and C"(-18, -24) C. A'(-30, -12) and C"(-18, -24) D. A'(-30, -12) and C"(-4, -6) E. A'(-10, -4) and C"(-4, -6)
What is the value of x in this diagram?
Please help
