Put it in an equation;
it is given that 36 is the price after the 40% discount, so;
36=X*40%
X here is the original price
36=X*(40/100)
40X=3600
X=90$
Hope this helps.
Answer:
Step-by-step explanation:
Yes, she can use this inequality and it does matter since the number of cars that the inequality provides will need to be equal to or more than that number in order for all the students to be able to go. Therefore, if we apply the inequality it would give us the minimum number of cars needed (n) like so
12 + 3n > 28 ... subtract 12 on both sides
3n > 16 ... divide both sides by 3
n > 5 1/3
Since there can't be 1/3 of a car and the number of cars needed must be higher than 5 1/3 then we would need a total of 6 cars to take all of the children.
Answer:
67.2 centimeters
Step-by-step explanation:
Answer:
Step-by-step explanation:
-4 is negative 4 witch is less then 4. -4 +4 =0
Answer:
A Pipe that is 120 cm long resonates to produce sound of wavelengths 480 cm, 160 cm and 96 cm but does not resonate at any wavelengths longer than these. This pipe is:
A. closed at both ends
B. open at one end and closed at one end
C. open at both ends.
D. we cannot tell because we do not know the frequency of the sound.
The right choice is:
B. open at one end and closed at one end
.
Step-by-step explanation:
Given:
Length of the pipe,
= 120 cm
Its wavelength
= 480 cm
= 160 cm and
= 96 cm
We have to find whether the pipe is open,closed or open-closed or none.
Note:
- The fundamental wavelength of a pipe which is open at both ends is 2L.
- The fundamental wavelength of a pipe which is closed at one end and open at another end is 4L.
So,
The fundamental wavelength:
⇒ 
It seems that the pipe is open at one end and closed at one end.
Now lets check with the subsequent wavelengths.
For one side open and one side closed pipe:
An odd-integer number of quarter wavelength have to fit into the tube of length L.
⇒
⇒ 
⇒
⇒ 
⇒
⇒ 
⇒
⇒
So the pipe is open at one end and closed at one end
.