I think the answer is C.
Hope this helps.
The relative frequency of students who are not seniors at this high school will be 82.96%.
<h3>How to find how much percent 'a' is of 'b'?</h3>
Suppose a number is 'a'
Suppose another number is 'b'
We want to know how much percent of 'b' is 'a'.
Then, it is calculated as:
P = a/b × 100
A local high school has 1,203 students with 367 freshmen, 382 sophomores, 249 juniors, and 205 seniors.
Then the relative frequency of students who are not seniors at this high school will be
P = 998/1203 × 100
P = 0.82959 × 100
P = 82.959%
P ≈ 82.96%
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The answer is 24/5 or 4 4/5 but if it is 11 on 5, the answer would be 44/5 or 8 4/5
Answer:
a) W'(t) = 1.51 -0.0138t + 0.000762t² pounds/day
Step-by-step explanation:
The median weight of a boy with age between 0 and 36 months is given by:
To find the rate of change of weight with respect to time, that is, the change in weight measured in pounds caused by a unit change in time, measured in days, simply derivate the weight function over time:
The rate of change is 1.51 -0.0138t + 0.000762t² pounds/day.
The good option to multiply the top equation by is <u>-4</u>
<h3>
REASON :-</h3>
This is because, when we solve the equations, in the left side of first equation :-
☆ -2 can be multiplied by <em>-4</em><em> </em>to get the value 8 on the left side of second equation.
☆ This can help in easier elimination in the given set of equations.
■ The process is to be done as per the given below way :
Now the 8x on both equations can be cut.