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Sauron [17]
3 years ago
10

Who want to talk about anything

Mathematics
2 answers:
Scorpion4ik [409]3 years ago
8 0
Hi. I really need answers!
Svetach [21]3 years ago
8 0
Helloooo I need answers too!
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Use a translator or whatever, just don't know how to do it. Will give most helpful answer brainliest, with an explanation and an
bekas [8.4K]
The answer is -60. this is because the signs implemented in front of numbers give it a sort pattern .

when there are two additions the last number after the positive sign will give a positive number 1 greater than the initial number for example + 5 + 6. Answer afterward will be + 7 and for negative sign eg: - 7 - 8 in the question will give the answer -8 the same number after a negative (-) sign .
Hope this helps
4 0
2 years ago
Which of the following statements is not true about the numbers 7 and -7?
leonid [27]

Answer:

incorrect is They have a sum of -14

4 0
3 years ago
PLEASE HELP ME ON THIS IT IS GEOMETRY PLEASE HELP ME DO NOT WASTE MY ANSWERS PLEASE HELP ME
sweet-ann [11.9K]
It’s hard to tell because there isn’t a visual. My guess is that it’s ASA~ and SAS~ because T is congruent to P and A and F have the same angle
5 0
2 years ago
7y + 4x - 10 + 5y - 5 + x
Lemur [1.5K]

Answer:

hope it helps u

Step-by-step explanation:

7y + 4x - 10 + 5y - 5 + x

= 7y+5y+4x+x–10–5

= 12y+5x–15

7 0
3 years ago
Read 2 more answers
A closed, rectangular-faced box with a square base is to be constructed using only 36 m2 of material. What should the height h a
kkurt [141]

Answer:

b=h=\sqrt{6} m

Step-by-step explanation:

Let

Bas length of box=b

Height of box=h

Material used in constructing of box=36 square m

We have to find the height h and base length b of the box to maximize the volume of box.

Surface area of box=2b^2+4bh

2b^2+4bh=36

b^2+2bh=18

2bh=18-b^2

h=\frac{18-b^2}{2b}

Volume of box, V=b^2h

Substitute the values

V=b^2\times \frac{18-b^2}{2b}

V=\frac{1}{2}(18b-b^3)

Differentiate w. r.t b

\frac{dV}{db}=\frac{1}{2}(18-3b^2)

\frac{dV}{db}=0

\frac{1}{2}(18-3b^2)=0

\implies 18-3b^2=0

\implies 3b^2=18

b^2=6

b=\pm \sqrt{6}

b=\sqrt{6}

The negative value of b is not possible because length cannot be negative.

Again differentiate w.r.t b

\frac{d^2V}{db^2}=-3b

At  b=\sqrt{6}

\frac{d^2V}{db^2}=-3\sqrt{6}

Hence, the volume of box is maximum at b=\sqrt{6}.

h=\frac{18-(\sqrt{6})^2}{2\sqrt{6}}

h=\frac{18-6}{2\sqrt{6}}

h=\frac{12}{2\sqrt{6}}

h=\sqrt{6}

b=h=\sqrt{6} m

7 0
3 years ago
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