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3 years ago

5

Max's town voted on a new speed limit. Of the votes received, 576 were in favor of the new speed limit and 64 were opposed. What

percentage of the votes were in favor of the new speed limit?

1 answer:

Inessa05 [86]3 years ago

8 0

9 I think that the Answer so if not delet this Answer

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The legs of a right triangle measure 5√2 cm and 4√2 cm. Find the area.

den301095 [7]

1/2(5 sqrt 2)(4 sqrt 2)= 20

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Find the area of the irregular shape. Round to the nearest tenth.

svp [43]

Given:
Irregular Shape:
Semi-circle and rectangle:

Area of a rectangle = l * w
Area of a semi-circle = (π r²)/2

Area of rectangle = 8 cm * 5 cm = 40cm²
Area of a semi-circle = (3.14 (4²))/2 = (3.14*16)/2 = 50.24/2 = 25.12cm²
4² is taken from diameter of 8cm divided by 2 to get the radius.

Total area = 40 cm² + 25.12 cm² = 65.12 cm²

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3 years ago

Find all of the critical points of p (t). p (t) = t 2 + 5t + 6.

svp [43]

Please, use " ^ " to denote exponentiation: p(t) = t^2 + 5t + 6.

To find the critical points, differentiate p(t) with respect to t, set the result = to 0, and then solve the resulting equation for t:

p '(t) = 2t + 5 = 0

Solving for t: 2t = -5, and so t = -5/2. (-5/2, p(-5/2)) is the critical point. That evaluates to (-5/2, -0.25). This happens to be the vertex of a parabola that opens up.

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3 years ago

A square napkin is folded in half on the diagonal and placed on the diameter of a round plate (see diagram below). If the folded

Crank

Answer:

$A=81(\pi-1)\ in^2$

Step-by-step explanation:

step 1

Find the area of the plate

The area of a circle is given by the formula

$A=\pi r^{2}$

we have

$r=18/2=9\ in$ ---> the radius is half the diameter

substitute

$A=\pi (9)^{2}\\A=81\pi\ in^2$

step 2

Find the area of the square napkin folded (is a half of the area of the square napkin)

we know that

The diagonal of the square is the same that the diameter of the plate

Applying Pythagorean theorem

$D^2=2b^2$

where

b is the length side of the square

we have

$D=18\ in$

substitute

$18^2=2b^2$

solve for b^2

$b^2=162\ in^2$ -----> is the area of the square

Divide by 2

$162/2=81\ in^2$

step 3

Find the area of the space on the plate that is NOT covered by the napkin

we know that

The area of the space on the plate that is NOT covered by the napkin, is equal to subtract the area of the square napkin folded (is a half of the area of the square napkin) from the area of the plate

so

$A=(81\pi-81)\ in^2$

simplify

$A=81(\pi-1)\ in^2$

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3 years ago

Linear equation: -1

Anika [276]

Answer:

The right answer is:

the addition property of equality and then the division property of equality

Step-by-step explanation:

Given equation and steps to solve it are:

Step 1: –3x – 5 = 13

Step 2: –3x = 18

Step 3: x = –6

In step two, -5 has to be removed from left hand side of the equation so additional property of equality will be used i.e. adding 5 on both sides

Similarly in the third step, to remove -3 with x , division property of equality will be used i.e. dividing both sides by -3

Hence,

The right answer is:

the addition property of equality and then the division property of equality

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