Y = cos(x)
sqrt(3)/2 = cos(30º)
dy = -sin(x)*dx
dy = -sin(30º)*(pi/180) = (1/2)*(pi/180)
y + dy = cos(x) - sin(x)dx
y + dy = sqrt(3)/2 - (1/2)*(pi/180) = 0.8573
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Answer: it will trave 56.89 meters before coming to rest.
Step-by-step explanation:
This is a geometric progression since the distance travelled (height) by the ball is reducing by a constant ratio, r. Since the number of times that the ball will bounce is infinite, then we would apply the formula for determining the sum of the terms in a geometric progression to infinity which is expressed as
S = a/(1 - r)
where
S = sum of the distance travelled by the ball
a = initial distance or height of the ball
r = common ratio
From the information given,
a = 128/9
r = (32/3)/(128/9) = 0.75
Therefore,
S = (128/9)/(1 - 0.75) = 56.89 meters
So you add whats in parentheses first which gives you -11 then you end up with -11(-3)
Which will equal 33 Thats your final awnser...
33
Answer:
a=11
Step-by-step explanation:
Answer:
See below.
Step-by-step explanation:
Average rate of change =( R(1008) - R(1001) ) / (1008 - 1001)
=[ 12(1008) - 0.005(1008)^2 - (12(1001) - 0.005(1001)^2) ] / 7
