All categories

4 years ago

PLEASE HELP!! Will mark brainliest

Mathematics

1 answer:

xenn [34]4 years ago

6 0

Triangular prism formula is 1/2 * height * base * other base, so 4.8 * 7.2 * 10 * 1/2 is 172.8.

You might be interested in

Jade and Kate were running around Lincoln Park. Jade started running at 12:00pm at a rate of 3 kilometers per hour. However, Kat

xxTIMURxx [149]

Answer: Kate ran about 4.82803 kilometers.

Step-by-step explanation:

So 1 mile ≈ 1.60934 kilometers.

To find out how far Kate ran in kilometers, you can multiply how far she ran in miles by 1.60934.

3 × 1.60934 ≈ 4.82803

Kate ran about 4.82803 kilometers.

8 0

3 years ago

Find the equation of the line with Slope = -4 and passing through (-1,8). Write your equation in the form

Thepotemich [5.8K]

Answer:

y= -4x+4

Step-by-step explanation:

y=mx+b

where x=-1, y=8, and m=-4

8=(-4)(-1)+b

8=4+b

4=b

Thus, y= -4x+4

8 0

3 years ago

Subtract.<br> 3- (-6)=<br> I’m not smart so plz just help!

RideAnS [48]

Answer:

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

11/24+w=11/12 I need help

DaniilM [7]

Answer:

w = 11/24

Step-by-step explanation:

11/24 + w = 11/12

w = 11/12 - 11/24

LCM of 12 and 24 is = 24

divide the denominators of both fractions by the LCM(24) and then multiply the results with the numerators

so we have w = 22 - 11 /24

w = 11/24

5 0

3 years ago

Simplify the sum. d^2-7d+12/d^2-d-6 + d^2+5d+6/d^2-2d-15

Law Incorporation [45]

Answer:

The sum is $\frac{2d^2-5d+24}{d^2-3d-10}$

Step-by-step explanation:

The given expression is

$\frac{d^2-7d+12}{d^2-d-6}+\frac{d^2+5d+6}{d^2-2d-15}$

These are all quadratic trinomials, so we split each of the middle terms to obtain,

$\frac{d^2-4d-3d+12}{d^2-3d+2d-6}+\frac{d^2+2d+3d+6}{d^2-5d+3d-15}$

We factor to obtain,

$\frac{d(d-4)-3(d-4)}{d(d-3)+2(d-3)}+\frac{d(d+2)+3(d+2)}{d(d-5)+3(d-5)}$

We factor further to obtain,

$\frac{(d-4)(d-3)}{(d-3)(d+2)}+\frac{(d+2)(d+3)}{(d-5)(d+3)}$

We cancel out the common factors to get,

$\frac{(d-4)}{(d+2)}+\frac{(d+2)}{(d-5)}$

The least common denominator is $(d+2)(d-5)$ .

We collect LCD to get

$\frac{(d-4)(d-5)+(d+2)(d+2)}{(d+2)(d-5)}$

We now expand to get,

$\frac{d^2-5d-4d+20+d^2+2d+2d+4}{d^2-5d+2d-10}$

We simplify to get,

$\frac{d^2-9d+20+d^2+4d+4}{d^2-3d-10}$

We simplify further to get,

$\frac{2d^2-5d+24}{d^2-3d-10}$

8 0

4 years ago