All categories

2 years ago

Answer Asap!

Mathematics

1 answer:

Dmitry_Shevchenko [17]2 years ago

5 0

Answer:

a) RTP

b) MN

c) x=7

Step-by-step explanation:

hope this helps

You might be interested in

Finley’s pumpkin had a mass of 6.5 kilograms before he carved it. After carving it the pumpkin had a mass of 3.9 kilograms. What

katen-ka-za [31]

Hello.

The percent decrease in the mass of the pumpkin for this case will be given by:
(100 - (3.9 / 6.5) * 100) =
(100-60) =40%

After carving it, the pumpkin decreases a percent of 40% in the mass.

Have a nice day

4 0

3 years ago

Read 2 more answers

User: Translate the following words to algebra symbols, using "n" as the variable. Seven is two less than twice a number.

muminat

7 = 2n - 2

n= a number so twice a number is 2n and 7 is 2 less than twice this number.

7 0

2 years ago

10.125 as a fraction

zubka84 [21]

Answer:

$\frac{81}{8}$

Step-by-step explanation:

$10.125=\frac{10125^{(125}}{1000}=\frac{81}{8}$

6 0

3 years ago

Read 2 more answers

Need help asap From top to bottom A B C D E

NNADVOKAT [17]

Answer:

B and D

Step-by-step explanation:

8 0

3 years ago

(x^2 - x^(1/2))/(1-x^(1/2))

Levart [38]

$\frac { \left( { x }^{ 2 }-{ x }^{ \frac { 1 }{ 2 } } \right) }{ \left( 1-{ x }^{ \frac { 1 }{ 2 } } \right) }$

$\\ \\ =\frac { \left( { x }^{ 2 }-\sqrt { x } \right) }{ \left( 1-\sqrt { x } \right) } \cdot 1$

$\\ \\ =\frac { \left( { x }^{ 2 }-\sqrt { x } \right) }{ \left( 1-\sqrt { x } \right) } \cdot \frac { \left( 1+\sqrt { x } \right) }{ \left( 1+\sqrt { x } \right) }$

$\\ \\ =\frac { { x }^{ 2 }+{ x }^{ 2 }\sqrt { x } -\sqrt { x } -x }{ 1+\sqrt { x } -\sqrt { x } -x }$

$\\ \\ =\frac { -\sqrt { x } \left( 1-{ x }^{ 2 } \right) -x\left( 1-x \right) }{ \left( 1-x \right) }$

$\\ \\ =\frac { -\sqrt { x } \left( 1+x \right) \left( 1-x \right) -x\left( 1-x \right) }{ \left( 1-x \right) }$

$\\ \\ =\frac { \left( 1-x \right) \left\{ -\sqrt { x } \left( 1+x \right) -x \right\} }{ \left( 1-x \right) }$

$\\ \\ =-\sqrt { x } \left( 1+x \right) -x\\ \\ =-{ x }^{ \frac { 1 }{ 2 } }\left( 1+{ x }^{ \frac { 2 }{ 2 } } \right) -x$

$\\ \\ =-{ x }^{ \frac { 1 }{ 2 } }-{ x }^{ \frac { 3 }{ 2 } }-x\\ \\ =-\sqrt { x } -\sqrt { { x }^{ 3 } } -x$

3 0

3 years ago

Read 2 more answers