Question

I will mark brainliest!

Answer 1

Answer:

$(1,13)$

Step-by-step explanation:

$p=-5t^2+18t$

$p=-2t+15$

$-5t^2+18t=-2t+15$

$-5t^2+20t=15$

$-5t^2+20t-15=0$

$-5(t^2-4t+3)=0$

$t^2-4t+3=0$

$(t-1)(t-3)=0$

$t_1=1$, $t_2=3$

Since we want the position to be when the ball FIRST crosses the path of the bird, we will need to choose $t_1=1$ as our solution.

Therefore, the position would be:

$p=-2t+15$

$p=-2(1)+15$

$p=-2+15$

$p=13$

$(1,13)$