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Lesechka [4]
3 years ago
10

45 points! i need help with 1-3

Mathematics
1 answer:
Advocard [28]3 years ago
6 0
To answer the 1 and 2 just put 0 on the variable other than the intercept you are looking for, if your looking for X, then Y = 0 so...

(Option D)1. -10x+5y=40
intercept on X
-10x + 5(0)=40
-10x=40 (divide by -10 to take x alone)
x= -4

intercept on Y
-10(0)+5y=40
5y=40 (divide by 5)
y=8

(Option D) 2. same procedure

int. X

5x +4y =80
5x + 4(0) = 80
x = 16

int y.
5(0) + 4y = 80
y = 20


3. just put in standard mode
y= (1/6)x + 4 (multiply by 6 so you have dont have fractions)

6y= x+ 24 (move x to the other side)

-x + 6y = 24

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