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Varvara68 [4.7K]
3 years ago
11

I thought this was much more easier for you! :)

Mathematics
1 answer:
monitta3 years ago
4 0
Problem 1)

The base of the exponential is 12 which is also the base of the log as well. The only answer choice that has this is choice B.

======================================================================
Problem 2)

log(x) + log(y) - 2log(z)
log(x) + log(y) - log(z^2)
log(x*y) - log(z^2)
log[(x*y)/(z^2)]

Answer is choice D

======================================================================
Problem 3)

log[21/(x^2)]
log(21) - log(x^2)
log(21) - 2*log(x)

This matches with choice B

======================================================================
Problem 4)

Ln(63) = Ln(z) + Ln(7)
Ln(63)-Ln(7) = Ln(z)
Ln(63/7) = Ln(z)
Ln(9) = Ln(z)
z = 9

======================================================================
Problem 5)

Ln(5x-3) = 2
5x-3 = e^2
5x = e^2+3
x = (e^2+3)/5

This means choice A is the answer
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3 years ago
For how many games Is the total cost of bowling equal for the two bowling establishments? Family Bowling- Game $4 Shoes $1 Knigh
skad [1K]

Step-by-step explanation:

Answer: If you play 4 games, the price will be the same in the two establishments.

Step-by-step explanation:

Ok, in Family Bowling we have:

$4 per game, plus $1 per shoes (the shoes are paid only one time).

Then, the price for X games, is:

Pa(X) = $4*X + $1.

In Knight Owl Bowling we have:

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Now, if we want to pay the same in both establishments, we have:

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$4*X + $1 = $3.75*X + $2

Now we should solve this for X.

$4*X - $3.75*X = $2 - $1 = $1

($4 - $3.75)*X = $1

$0.25*X = $1

X = $1/$0.25 = 4.

If you play 4 games, the price will be the same in the two establishments.

Darmaidayxx and 34 more users found this answer helpful

THANKS

25

4.6

(9 votes)

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1 year ago
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