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frutty [35]
4 years ago
12

The population of a town doubled every 5 years from 1960 to 1975. What is the percentage increase in population in this period ?

Mathematics
1 answer:
777dan777 [17]4 years ago
5 0

Answer:

<h2>800%</h2>

Step-by-step explanation:

Let p represent the population

in 1965 → the population becomes 2p

in 1970 → the population becomes 2(2p) = 4p

in 1975 → the population becomes 2(4p) = 8p

 p  ——————> 100%

8p  ————-—-> x%

then

x=\frac{8p*100}{p}=800

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-3x-2y=-6<br> -3x+2y=18<br> (?,?)
lozanna [386]

\left \{ {-3x-2y = -6} \atop {-3x+2y=18} \right. \left \{ {-6x=12} \atop {-3x+2y=18} \right.  \left \{ {x=-2} \atop {y=6} \right.

The answer: ( x ; y ) = ( -2 ; 6 )

Ok done. Thank to me :>

8 0
3 years ago
The circumference of a circle with a radius of 5, using 3.14 for pi, to the nearest tenth
Anuta_ua [19.1K]

Answer:

Your answer is 31.4 units squared

Step-by-step explanation:

By doing 2πr, you'll get your answer.

2*3.14*5 = 2*15.7 = 31.4

3 0
4 years ago
Two angles are supplementary. One angle measurement is 30 more than the other. What is the measure of the smaller angle?
Drupady [299]
60 because it has to equal at least 90  degrees 

4 0
3 years ago
Above is a table that gives the interest per every $100 financed. Use the table to determine the annual percentage rate for a 35
jonny [76]

The annual percentage rate for a 35 month loan that charges $22.38 per every $100 financed is seen from the table to be 14%.

<h3>How to determine Annual Percentage Rate?</h3>

From the table, the APR for 35 months loan that charges $22.38 per every $100 financed is seen to be 14%.

Thus, we can conclude that the annual percentage rate for a 35 month loan that charges $22.38 per every $100 financed is seen from the table to be 14%.

Read more about Annual Percentage Rate at; brainly.com/question/11686424

#SPJ1

5 0
3 years ago
Write -0.32 as a fraction in simplest form.
mariarad [96]

Answer:

-0.32

-32/100

-8/25

Step-by-step explanation:

-8/25

8 0
3 years ago
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