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andre [41]
3 years ago
5

HELPP!!! BRAINLYESTTTTT!!!!!! GRAPH THE FUNCTION:

Mathematics
1 answer:
Roman55 [17]3 years ago
5 0

Answer:


Step-by-step explanation:

We are given the function f(x) = -3/4(x) +6.

We know that the slope intercept form of a line is y = mx + b

Here, the slope m = -3/4.

The y-coordinate of the y intercept is b = 6 so the y-intercept is at the point (0,6) [x is always 0 at the y-intercept]

If you have to points you can graph the line, we only have the point (0,6).

To find the second point we use the slope.

We add the bottom point of the slope to the x coordinate of the y-intercept and we add the top part of the slope to the y coordinate of the y-intercept, so our second point is (0 + 4, 6 +(-3)) = (4, 3).

You then plot the points we have: (0,6) and (4,3) and draw the line through them.


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Area of a triangle with points at (-9,5), (6,10), and (2,-10)
Ann [662]
First we are going to draw the triangle using the given coordinates. 
Next, we are going to use the distance formula to find the sides of our triangle.
Distance formula: d= \sqrt{(x_{2}-x_{1})^2+(y_{2}-y_{1})^2}

Distance from point A to point B:
d_{AB}= \sqrt{[6-(-9)]^2+(10-5)^2}
d_{AB}= \sqrt{(6+9)^2+(10-5)^2}
d_{AB}= \sqrt{(15)^2+(5)^2}
d_{AB}= \sqrt{225+25}
d_{AB}= \sqrt{250}
d_{AB}=15.81

Distance from point A to point C:
d_{AC}= \sqrt{[2-(-9)]^2+(-10-5)^2}
d_{AC}= \sqrt{(2+9)^2+(-10-5)^2}
d_{AC}= \sqrt{11^2+(-15)^2}
d_{AC}= \sqrt{121+225}
d_{AC}= \sqrt{346}
d_{AC}= 18.60

Distance from point B from point C
d_{BC}= \sqrt{(2-6)^2+(-10-10)^2}
d_{BC}= \sqrt{(-4)^2+(-20)^2}
d_{BC}= \sqrt{16+400}
d_{BC}= \sqrt{416}
d_{BC}=20.40

Now, we are going to find the semi-perimeter of our triangle using the semi-perimeter formula:
s= \frac{AB+AC+BC}{2}
s= \frac{15.81+18.60+20.40}{2}
s= \frac{54.81}{2}
s=27.41

Finally, to find the area of our triangle, we are going to use Heron's formula:
A= \sqrt{s(s-AB)(s-AC)(s-BC)}
A=\sqrt{27.41(27.41-15.81)(27.41-18.60)(27.41-20.40)}
A= \sqrt{27.41(11.6)(8.81)(7.01)}
A=140.13

We can conclude that the perimeter of our triangle is 140.13 square units.

3 0
2 years ago
Find the length of the third side. If necessary,<br> round<br> to<br> the nearest tenth.<br> 4<br> 7
Natalija [7]
Can you show a picture of the question
8 0
3 years ago
Read 2 more answers
Solve the proportions
DanielleElmas [232]

Do cross multiply or butterfly.   For example first one. 18/x=6/10  So cross multiply  18×10 =6x 180=6x Divide both sides by 6 to get x alone 180÷6=30 So x =30  Do the same to rest

4 0
3 years ago
What is the equation for the translation of x2 + y2 = 16 seven units to the right and five units up?
asambeis [7]

Answer:

  • (x − 7)2 + (y − 5)2 = 16

Step-by-step explanation:

The given circle has equation

\sf \: x^2+y^2=16x

The equation of a circle with center (h,k) and radius r units is

\sf(x-h)^2+(y-k)^2=r^2(x−h)

\sf(x-7)^2+(y-5)^2=4^2(x−7)

\sf(x-7)^2+(y-5)^2=16(x−7)

<h2>❖ Tip❖ :- </h2>

This is the equation that has its center at the origin with radius 4 units.

When this circle is translated seven units to the right and five units up, then the center of the circle will now be at (7,5).

6 0
2 years ago
A concert hall has 8,000 seats and two categories of ticket prices, $29 and $34. Assume that all seats in each category can be s
Greeley [361]

Using a system of equations, it is found that:

  • For a profit of $255,000, 3400 tickets of $29 and 4600 tickets of $34 must be sold.
  • For a profit of $271,000, 200 tickets of $29 and 7800 tickets of $34 must be sold.
  • For a profit of $235,000, 7400 tickets of $29 and 600 tickets of $34 must be sold.

--------------------

The variables of the system are:

  • x, which is the number of $29 tickets sold.
  • y, which is the number of $34 tickets sold.

Total of 8,000 seats, all can be sold, thus:

x + y = 8000 \rightarrow x = 8000 - y

--------------------

For a profit of $255,000, we have that:

29x + 34y = 255000

29(8000 - y) + 34y = 255000

5y = 23000

y = \frac{23000}{5}

y = 4600

x = 8000 - 4600 = 3400

For a profit of $255,000, 3400 tickets of $29 and 4600 tickets of $34 must be sold.

--------------------

For a profit of $271,000, we have that:

29x + 34y = 271000

29(8000 - y) + 34y = 271000

5y = 39000

y = \frac{39000}{5}

y = 7800

x = 8000 - 7800= 200

For a profit of $271,000, 200 tickets of $29 and 7800 tickets of $34 must be sold.

--------------------

For a profit of $235,000, we have that:

29x + 34y = 235000

29(8000 - y) + 34y = 235000

5y = 3000

y = \frac{3000}{5}

y = 600

x = 8000 - 600 = 7400

For a profit of $235,000, 7400 tickets of $29 and 600 tickets of $34 must be sold.

A similar problem is given at brainly.com/question/22826010

3 0
3 years ago
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