Question

the number 144 is multiplied with 2^-3 , 12^-1 and 3^-2 consecutively . Find the final product pls quick :)

Answer 1

Answer:

$\boxed{\sf \ \ \ \dfrac{1}{6} \ \ \ }$

Step-by-step explanation:

Hello

when you multiply by $2^{-3}$

it is equivalent to divide by $2^3$

so we are looking for

$144*2^{-3}*12^{-1}*3^{-2}=\dfrac{144}{2^3*12*3^2}=\dfrac{9*16}{2^3*12*3^2}\\=\dfrac{3^2*2^4}{2^3*12*3^2}=\dfrac{2}{12}=\dfrac{1}{6}$

hope this helps

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