= [7+7 <span>÷ 7] + 4.12
= [7+1] + 4.12
= 8 + 4.12
= 12.12
</span>
Answer:
see explanation
Step-by-step explanation:
The nth term of an AP is
= a₁ + (n - 1)d
where a₁ is the first term and d the common difference
Given a₅ is double a₇ , then
a₁ + 4d = 2(a₁ + 6d) , that is
a₁ + 4d = 2a₁ + 12d ( subtract a₁ from both sides )
4d = a₁ + 12d ( subtract 12d from both sides )
- 8d = a₁
The sum of n terms of an AP is
=
[ 2a₁ + (n - 1)d ] , substitute values
=
( 2(- 8d) + 16d)
= 8.5(- 16d + 16d)
= 8.5 × 0
= 0
Answer:
The areas of the squares adjacent to two sides of a right triangle are shown below.
What is the area of the square adjacent to the third side of the triangle?
units^2
2
Step-by-step explanation:
Answer:
20
Step-by-step explanation: