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Natasha2012 [34]
4 years ago
14

A deli has a special one-day event to celebrate its anniversary. On the day of the event, every eighth customer receives a free

drink. Every twenty-eighth customer receives a free sandwich. If 200 customers show up for the event, how many of the customers will receive both a free drink and a free sandwich?
Mathematics
2 answers:
enyata [817]4 years ago
4 0

Answer:

the number of common customers are 8 in number

garri49 [273]4 years ago
4 0

Answer: The answer is just 3 people will get BOTH the free drink and free sandwich.

Step-by-step explanation:

Every 8th = 1 free drink

Every 28th = 1 free sandwich

200 costumers showed

Add 28 to 28 until you reach the closest to 200 so: 28,56,84,112,140,168,196

Then add 8 to 8 until 200, every number that match the 28th sequence is 1 costumer that receives 1 drink and 1 sandwich

The match numbers are 56,112,168

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Find 'x' in the following ​
Juli2301 [7.4K]

Answer:

x = 130

Step-by-step explanation:

Sum of all the angle of quadrilateral = 360°

50 + 45 + 35 + ∠ADC = 360

                130 + ∠ADC = 360

                         ∠ADC = 360 - 130

                         ∠ADC = 230

x = Reflex ∠ADC

  = 360 - 230

  = 130

6 0
3 years ago
Read 2 more answers
REAL ANSWERS PLEASE AND NOT JUST FOR THE POINTS 20 EACH
Fed [463]
A+b=(-3n+2)+(5n-7)

=(5-3n)+(2-7)

=2n-5


Came up with the same answer as the first guy
4 0
3 years ago
3x + 2(4x - 4) = 3 4 3 2 1
rjkz [21]

Answer:

<u><em>X=1</em></u>

Step-by-step explanation:

6 0
3 years ago
Each week Tim wants to increase the number of sit ups he does by to set up’s the first week he does 15 sit ups each day. Write a
Alex17521 [72]

Answer: f(n+ 1) = f(n) + 2, where f(1) = 15.

4 0
4 years ago
"how many different rectangles" can you draw that have a perimeter of 12, 14
amm1812
Perimeter of rectangle = length + length + width + width

To find the combinations, think of two numbers that each multiplied by 2 and added up to give 12 or 14

Rectangle with perimeter 12

Say we take length = 2 and width = 3
Multiply the length by 2 = 2 × 2 = 4
Multiply the width by 3 = 2 × 3 = 6
Then add the answers = 4 + 6 = 10
This doesn't give us perimeter of 12 so we can't have the combination of length = 2 and width = 3

Take length = 4 and width = 2
Perimeter = 4+4+2+2 = 12
This is the first combination we can have

Take length = 5 and width = 1
Perimeter = 5+5+1+1 = 12
This is the second combination we can have

The question doesn't specify whether or not we are limited to use only integers, but if it is, we can only have two combinations of length and width that give perimeter of 12

length = 4 and width = 2
length = 5 and width = 1
--------------------------------------------------------------------------------------------------------------

Rectangle with perimeter of 14

Length = 4 and width = 3
Perimeter = 4+4+3+3 = 14

Length = 5 and width = 2
Perimeter = 5+5+2+2 = 14

Length = 6 and width = 1
Perimeter = 6+6+1+1 = 14

We can have 3 different combinations of length and width





3 0
3 years ago
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