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Natasha2012 [34]
3 years ago
14

A deli has a special one-day event to celebrate its anniversary. On the day of the event, every eighth customer receives a free

drink. Every twenty-eighth customer receives a free sandwich. If 200 customers show up for the event, how many of the customers will receive both a free drink and a free sandwich?
Mathematics
2 answers:
enyata [817]3 years ago
4 0

Answer:

the number of common customers are 8 in number

garri49 [273]3 years ago
4 0

Answer: The answer is just 3 people will get BOTH the free drink and free sandwich.

Step-by-step explanation:

Every 8th = 1 free drink

Every 28th = 1 free sandwich

200 costumers showed

Add 28 to 28 until you reach the closest to 200 so: 28,56,84,112,140,168,196

Then add 8 to 8 until 200, every number that match the 28th sequence is 1 costumer that receives 1 drink and 1 sandwich

The match numbers are 56,112,168

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Please help me with the problem
mixas84 [53]
Let's see what we're working on here 

\frac{1}{2}  - 2(m) =?
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Simplify this → \frac{1}{2}

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\frac{2(m)(2)}{2}

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Multiply( ×) the number -1 to your sides for this part of the equation 

Therefore, the value of m is \frac{1}{4}
m =  \frac{1}{4}


3 0
3 years ago
Read 2 more answers
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Answer:

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