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ivann1987 [24]
2 years ago
12

THE RATIO OF ZOE’S MONEY TO PERRY’S MONEY WAS 2:3. AFTER PERRY GAVE ½ OF HIS MONEY TO ZOE, ZOE HAD $210. HOW MUCH MONEY DID ZOE

HAVE TO START?
Mathematics
1 answer:
liberstina [14]2 years ago
8 0
Jkldmjslsjhuu hi phhenehkuuehqkheojhejekekebheeknebejejebrjbiemebekeneoeke
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Hey guys please help with this questoin Find (x+y) ÷ (x-y) if x=5/4 y=-1/3​
pogonyaev

Answer:

<h2>11/19</h2>

Step-by-step explanation:

(\frac{5}{4} + (-\frac{1}{3})) \div (\frac{5}{4} - (-\frac{1}{3}))\\\\\frac{\frac{5}{4}+\left(-\frac{1}{3}\right)}{\frac{5}{4}-\left(-\frac{1}{3}\right)}\\\\\mathrm{Remove\:parentheses}:\quad \left(-a\right)=-a,\:-\left(-a\right)=a\\=\frac{\frac{5}{4}-\frac{1}{3}}{\frac{5}{4}+\frac{1}{3}}\\\\\mathrm{Join}\:\frac{5}{4}+\frac{1}{3}:\quad \frac{19}{12}\\\mathrm{Join}\:\frac{5}{4}-\frac{1}{3}:\quad \frac{11}{12}\\\\=\frac{\frac{11}{12}}{\frac{19}{12}}\\\\=\frac{11\times\:12}{12\times \:19}

= 11/19

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3 years ago
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Free 25 points TwT..
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Step-by-step explanation:

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Anyone, I need help... Just answer the 6 (c)....and also proper working.☺️
Ainat [17]

Answer:

(i) The area of the rabbit cage when the width is 5.2 m is 81.5 m²

(ii) The area of the rabbit cage if Wilson has 40 meters of wire mesh is 75 m²

Step-by-step explanation:

(i) The given relation of the area, A to the width P of the rabbit cage is A = 3·p²

The graph of the function between the values of 0 and 6 inclusive is found as follows;

A,              3·p²

0,               0

1,                1

2,               12

3,               27

4,               48

5,               75

6,               108

Please find attached the graph of A to 3·p²

From the graph, we have when the the width, p, of the rabbit cage = 5.2, the area, A ≈ 81.5 m²

The area of the rabbit cage when the width is 5.2 m = 81.5 m²

(ii) Also from the graph given that the total wire mess with Wilson = 40 meters, we have;

The formula for the perimeter of the cage = The formula for the perimeter of a rectangle = 2×length + 2×width

The formula for the perimeter of the cage = 2×3×p + 2× p = 8·p

Where the total length of the wire mesh available = 40 meters for the cage

The 40 meters of wire mesh will be used round the perimeter of the cage

∴ 40 m. = 8·p

p = 40/8 = 5 m.

At p = 5 m. the area is given as A = 75 m².

Therefore, the area of the rabbit cage if Wilson has 40 meters of wire mesh = 75 m².

5 0
3 years ago
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