Polar coordinates=<span>(6sqrt 2, 3pi/4)=(r, theta)→r=6 sqrt 2, theta=3pi/4
Rectangular coordinates=(x,y)=?
x=r cos theta=(6 sqrt 2) cos(3pi/4)=(6 sqrt 2)(-sqrt 2 / 2)
x=-3 (sqrt 2)^2=-3(2)→x=-6
y=r sin theta=(6 sqrt 2) sin (3pi/4)=(6 sqrt 2)(sqrt 2 / 2)
y=3 (sqrt 2)^2=3(2)→y=6
Rectangular coordinates of the point = (x,y) =(-6,6)
Answer: Option a. (-6,6) </span>
Answer:
the answer is d
Step-by-step explanation:
i dont really know why but the circle thats not colored in is on -9 and the one that is colored in is on 6 so yeah
11pi/6 is in 4th quadrant.
The reference angle is pi/6 because 11pi/6 is pi/6 radians away from 'x' axis.
In 4th quadrant, sin is negative and cos is positive, therefore tan is negative.
This means: