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3 years ago

6

Find the critical value za/2 that corresponds to a 82% confidence level.

1 answer:

Lady_Fox [76]3 years ago

6 0

Finding critical value of Z at 82% confidence level:

Step 1: α% = 100%-82% = 18%
Step 2: α = 18% = 0.18
Step 3: α/2 = 0.18/2 = 0.09
Step 4: 1- α/2 = 1-0.09 = 0.91
Step 5: Critical value of Z at 82%confidence level = Z at 0.91 (from Z tables) ≈ 1.34

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An anthropologist studies a woman's femur that was uncovered in Madagascar. To estimate the woman's height, he uses the equation

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Answer:

The inequality best represents the length of the femur that would suggest the woman had a height greater than 160 cm is:

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Step-by-step explanation:

Woman's height (cm): h = 60 + 2.5 f

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3 years ago

Lynee bought some produce. She bought a bag of grapefruit, 1 5/8 pounds of apples, and 2 3/16 pounds of bananas. The total weigh

iragen [17]

Given:

Lynee bought a bag of grapefruit, $1\dfrac{5}{8}$ pounds of apples, and $2\dfrac{3}{16}$ pounds of bananas.

The total weight of her purchase was $7\dfrac{1}{2}$ pounds.

To find:

The weight of the bag of grapefruit.

Solution:

We have,

Weight of apples = $1\dfrac{5}{8}$ pounds.

Weight of bananas = $2\dfrac{3}{16}$ pounds.

Total weight of her purchase = $7\dfrac{1}{2}$ pounds.

Let x be the weight of the bag of grapefruit.

$x+1\dfrac{5}{8}+2\dfrac{3}{16}=7\dfrac{1}{2}$

$x+\dfrac{1(8)+5}{8}+\dfrac{2(16)+3}{16}=\dfrac{7(2)+1}{2}$

$x+\dfrac{13}{8}+\dfrac{35}{16}=\dfrac{15}{2}$

$\dfrac{16x+26+35}{16}=\dfrac{15}{2}$

Multiply both sides by 16.

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$16x=120-61$

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$x=\dfrac{59}{16}$

$x=3\dfrac{11}{16}$

Therefore, the weight of a bag of grapefruit is $3\dfrac{11}{16}$ pounds.

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3 years ago