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likoan [24]
3 years ago
10

Use a sum or difference identity to find exact value of sin 255.

Mathematics
1 answer:
vagabundo [1.1K]3 years ago
5 0
Sin (x + y) = sin x cos y + cos x sin y 

<span>sin 255 </span>
<span>= sin (210 + 45) </span>
<span>= sin 210 cos 45 + cos 210 sin 45 </span>
<span>= (-1/2)(√(2)/2) + (-√(3)/2)(√(2)/2) </span>
<span>= -√(2)/4 + (-√(6)/4) </span>
<span>= -√(2)/4 - √(6)/4 </span>
<span>= (-√(2) - √(6)) / 4</span>
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Given: PQ = RS, QR = 11, QS = x + 19, and RS = 2X. Find QS.<br> Can someone help
nalin [4]

QS =25

Step-by-step explanation:

QR + RS = QS

18 + (x-11) =2x-11

7 +x =2x -11

18=x

Plug in x

2(18) -11

36-11

QS=25

18 + (18-11) = 2(18)- 11

18+ 7 = 36 -11

25= 25

True

Answer:

QS + QR > RS

QR + RS > QS

RS + QS > QR

Step-by-step explanation:

Hope it helps you!

3 0
3 years ago
Which of the following equations has a graph that passes through (3, 3) and has a slope of −2?
Tatiana [17]

Answer:

y - y1 = m(x - x1)

y - -3 = 3(x - 1)

y + 3 = 3x - 3

     y = 3x - 3 - 3

     y = 3x - 6

     y = 3x - 6

Step-by-step explanation:

Thie equation is in slope-intercept form (y = mx + b)

The y-intercept is -6 .... ((0, -6) is one point on the line.

It is given that (1, -3) is also on the line. So to graph, plot those

2 points and connect them with a line.

7 0
3 years ago
Read 2 more answers
If there are 120 boys in the group, how many boys and girls are there TOTAL? Use the tape diagrams to solve.
Firdavs [7]
There are no girls???
6 0
2 years ago
I really need help please (links will be reported)
mrs_skeptik [129]

Answer: all the ones that do not have a negative sign in front easy.

7 0
3 years ago
Q7.
VLD [36.1K]

Answer:

10

Step-by-step explanation:

Let c = sum of ages of all children.

mean age of all children = c/15 = 7

c = 15 * 7 = 105

The sum of the ages of all children is 105.

Let b = sum of ages of the 9 boys.

mean age of boys = b/9 = 5

b = 9 * 5 = 45

The sum of the ages of the boys is 45.

The sum of the ages of the girls is c - b.

c - b = 105 - 45 = 60

The number of girls is 15 - 9 = 6

mean age of girls = (sum of ages of the girls)/(number of girls) =

= 60/6 = 10

3 0
3 years ago
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