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3 years ago

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The partial blueprint for an office building shows one outer wall and a perpendicular inner wall. Which of the following could b

e the equation of the inner wall, if the outer wall is represented by the equation y = 2/5x − 1?
Please help I am struggling really badly

1 answer:

Aloiza [94]3 years ago

5 0

Answer:

The equation of the perpendicular line:

2x + 5y = ╼ 15

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How do you factor 5x^2 = 10x

denis-greek [22]

$5x^2 = 10x$

$5x^2-10x=10x-10x$

$5x^2-10x=0$

Use quadratic formula

$\quad x_{1,\:2}=\dfrac{-b\pm \sqrt{b^2-4ac}}{2a}$

$\mathrm{For\:}\quad a=5,\:b=-10,\:c=0:\quad x_{1,\:2}=\dfrac{-\left(-10\right)\pm \sqrt{\left(-10\right)^2-4\cdot \:5\cdot \:0}}{2\cdot \:5}$

$x=\dfrac{-\left(-10\right)+\sqrt{\left(-10\right)^2-4\cdot \:5\cdot \:0}}{2\cdot \:5}:\quad 2$

$x=\dfrac{-\left(-10\right)-\sqrt{\left(-10\right)^2-4\cdot \:5\cdot \:0}}{2\cdot \:5}:\quad 0$

$x=2,\:x=0$

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3 years ago

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Is -5 greater than -10

kupik [55]

Answer:

yes -5 is greater than -10 because on a timeline -5 comes before -10

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Triangle abc is similar to triangle FGH solve for p plebs.

12345 [234]

The value of <em>p </em>is 21

Step-by-step explanation:

ΔABC ~ ΔFGH

$\frac{ab}{fg} = \frac{bc}{gh} \\ \frac{35}{p} = \frac{10}{6} \\ p = \frac{35 \times 6}{10} \\ p = \frac{210}{10} \\ p = 21 \\ \\ or \\ \\ \frac{ab}{fg} = \frac{ac}{fh} \\ \frac{35}{p} = \frac{30}{18} \\ p = \frac{35 \times 18}{30} \\ p = \frac{630}{30} \\ p = 21$

So, the value of <em>p</em> is 21

<em>Hope </em><em>it </em><em>helpful </em><em>and </em><em>useful </em><em>:</em><em>)</em>

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3 years ago

What is the value of the natural logarithm when x =0.6 is rounded to the nearest hundredth

Bezzdna [24]

We are tasked to determine the natural logarithm when x = 0.6.
x = 0.6, applying natural logarithm on both sides, we have it:
ln x = ln 0.6 using a scientific calculator, enter ln 0.6 and then this would give an answer of -0.5108256238
As per instruction, we are required to round the answer to the nearest hundredth such as the final answer is -0.51.

The answer is the letter "B".

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On a coordinate plane, rhombus W X Y Z is shown. Point W is at (7, 2), point X is at (5, negative 1), point Y is at (3, 2), and

Otrada [13]

Answer:

$P = 4\sqrt{13}$

Step-by-step explanation:

Given

$W = (7, 2)$

$X = (5, -1)$

$Y = (3, 2)$

$Z =(5, 5)$

Required

The perimeter

To do this, we first calculate the side lengths using distance formula

$d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2$

So, we have:

$WX = \sqrt{(5- 7)^2 + (-1 - 2)^2$

$WX = \sqrt{13}$

$XY = \sqrt{(3-5)^2 + (2--1)^2}$

$XY = \sqrt{13}$

$YZ = \sqrt{(5-3)^2 + (5-2)^2}$

$YZ = \sqrt{13}$

$ZW = \sqrt{(7 - 5)^2 + (2 - 5)^2}$

$ZW = \sqrt{13}$

The perimeter is:

$P = WX + XY + YZ + ZW$

$P = \sqrt{13}+\sqrt{13}+\sqrt{13}+\sqrt{13}$

$P = 4\sqrt{13}$

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