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2 years ago

Can somebody plz help answer these questions correctly thanks! (Grade7math) btw :)

Mathematics

1 answer:

Monica [59]2 years ago

7 0

Answer:

1. both boxes 3

2. both boxes 7

3. both boxes 5

4. both boxes 2

5. top box 12 bottom 18

6. top box 9 bottom box 11

7. top box 42 bottom box 60

8. top box 4 bottom box 5

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3(n-4)=5n+4 What does n equal?

Angelina_Jolie [31]

Your answer is n=2. thank me if this helped you. :)

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3 years ago

Please help me, I need help so bad. make sure to write the full calculation please. If you want bonus points please answer the s

cluponka [151]

Answer:

1. About 9 left. 2. £21 left

Step-by-step explanation:

First, you do 65 ÷ 3 = 21.7 if rounding to the tenths, 21.67 if to the hundredths, and so on. Then you do 21.67 - 12 = 9.67. But since it is cards, I would say about 9 left.

First you add the £20 to the £70 to get £90. then you multiply 7×3 to get £21 spent on books. After that, multiply 12×4 to get £48 spent on games. then do 48 + 21 = 69. 90-69= 21.

Here is the equation....

(70+20)-[(7×3)+(12×4)] = £21

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2 years ago

Find the value of x if g(x) = - 18 for g(x) = 2x - 8

nalin [4]

Hi there!

$\large\boxed{x = -5}$

Find the value of 8 by substituting in -18 for g(x):

-18 = 2x - 8

Add 8 to both sides:

-10 = 2x

Divide both sides by 2:

-10/2 = 2x/2

x = -5

8 0

2 years ago

Read 2 more answers

What is the kinetic Energy of a 110 kg linebacker rushing towards his football

Leviafan [203]

Answer:

The Kinetic energy of the 110 kg linebacker is 1375 J

Solution:

The kinetic energy of an object is the energy produced by its velocity. Kinetic energy of an object is directly proportional to the mass and the square of the its velocity.

Therefore, the formula for kinetic energy is

$KE=\frac{1}{2} \times m v^{2}$

Here, The linebacker’s mass m = 110 kg

The linebacker’s velocity v = 5 m/s

So by substituting the values,

The kinetic energy of linebacker is

$K E=\left(\frac{1}{2} \times 110 \times 5 \times 5\right) \text { Joules } \\\\ \Rightarrow (\frac{2750}{2}) Joules = 1375 Joules$

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2 years ago

A car the normally sells for 20,000 is on sale for 18,000 what is the discount rate?

balandron [24]

(20,000-18,000)÷20,000=0.1=10%

6 0

3 years ago