<span>280
I'm assuming that this question is badly formatted and that the actual number of appetizers is 7, the number of entres is 10, and that there's 4 choices of desserts. So let's take each course by itself.
You can choose 1 of 7 appetizers. So we have
n = 7
After that, you chose an entre, so the number of possible meals to this point is
n = 7 * 10 = 70
Finally, you finish off with a dessert, so the number of meals is:
n = 70 * 4 = 280
Therefore the number of possible meals you can have is 280.
Note: If the values of 77, 1010 and 44 aren't errors, but are actually correct, then the number of meals is
n = 77 * 1010 * 44 = 3421880
But I believe that it's highly unlikely that the numbers in this problem are correct. Just imagine the amount of time it would take for someone to read a menu with over a thousand entres in it. And working in that kitchen would be an absolute nightmare.</span>
Answer:
Step-by-step explanation:
−4−8+j
=−4+−8+j
Combine Like Terms:
=−4+−8+j
=(j)+(−4+−8)
=j+−12
Answer:
=j−12
If the width is 9x², then the length is 27x^5+9x^4-18x^3/9x², which equals 3x³+x²+2x. ☺☺☺☺
Answer:
x=-5-2yi/3+4i
y=3xi/2+6+15i/2
Step-by-step explanation:
Isolate the variable by dividing each side by factors that don't contain the variable.
Multiply the numerator by the numerator (top number).
Multiply the denominator by the denominator (bottom number).
So 3 x 6 = 18
And 5 x 7 = 35
= 18/35
