Answer:
x= 1 , y=4
Step-by-step explanation:
x-y= -3 => Equation 1
x+5y= 21 => Equation 2
<u>Substitut</u><u>ion</u><u> </u><u>Method</u><u>:</u>
<u>Substitu</u><u>te</u><u> </u><u>Equation</u><u> </u><u>1</u>=>
x=y-3 <= Equation 3
Put x=y-3 in Equation 2:
x+5y=21
( y-3)+5y=21
y-3+5y=21
6y-3=21
6y=21+3
6y=24
y=24÷6
y=4
Put y=4 in Equation 1:
x-y= -3
x-4=-3
x=4-3
x=1
Hope this helps :)
Answer:
3: 97
10: 97
9: 83
5: 97
7: 83
16: 97
Im 100% on these answers bc Ive already taken this class :)
Answer:
x=36
y=9
Step-by-step explanation:
Plug in 0 for x to find the y-intercept
0 + 4y = 36
4y = 36
y = 9
y-intercept (0, 9)
Plug in 0 for y to find the x-intercept
x + 4(0) = 36
x = 36
x-intercept (36, 0)
Strange question, as normally we would not calculate the "area of the tire." A tire has a cross-sectional area, true, but we don't know the outside radius of the tire when it's mounted on the wheel.
We could certainly calculate the area of a circle with radius 8 inches; it's
A = πr^2, or (here) A = π (8 in)^2 = 64π in^2.
The circumference of the wheel (of radius 8 in) is C = 2π*r, or 16π in.
The numerical difference between 64π and 16π is 48π; this makes no sense because we cannot compare area (in^2) to length (in).
If possible, discuss this situatio with your teacher.