The circles area would equal 380.13 miles
Area=pi (or 3.14) times the radius to the second power. [A=3.14r(2)]
Answer:
∠DFE ≅ ∠DFG
Step-by-step explanation:
we know that
Triangles are congruent by SAS, if any pair of corresponding sides and their included angles are equal in both triangles
In this problem we have that
The pair of corresponding sides that are equal are
EF=GF and DF (is the same side for both triangles)
The included angle are ∠DFE and ∠DFG
therefore
The additional information needed to prove that triangles DEF and DGF are congruent by SAS is that angles ∠DFE and ∠DFG are equal
so
∠DFE ≅ ∠DFG
Answer:
The sum of the squares of the two sides equals the square of the hypotenuse (a² + b² = c²).
Let's say you have a triangle with a 90º angle (also known as a right angle). The two equal legs are a and b while the hypotenuse is the longer side. Hypotenuse is and always will be c.
Here's a problem:
c ⊿ a (12)
b (6)
C is missing, we have to find C, so here's what we do:
Step 1: You square all the numbers in the equation
12² + 6² = c²
↓
144 + 36 = c
Step 2: You add 144 + 36 and you get 180
Step 3: Then you find the square root >>
and you get ≈13.4
Now sometimes, the a or b would be missing, for example:
c (13)⊿ a
b (5)
A is missing (when a or b is missing, use the following formula, do not use the same formula when c is missing)
Step 1: You square all the numbers in the equation
a² + 5² = 13²
a + 25 = 169
For this next part, you must subtract a or b (in this case, b) on both sides, for example:
25 – 25 = 169 - 25
25 – 25 cancels itself out so now we subtract 169 by 25 and we get 144.
Then we find the square root of 144 and we get 12
I hope this helps :)