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2 years ago

Help help what’s the value of x measure of c

Mathematics

2 answers:

garri49 [273]2 years ago

5 0

Answer:

(a) x = 29

(b) m∠C = 93°

Step-by-step explanation:

(a) The sum of the interior angles of a triangle = 180°

⇒ m∠A + m∠B + m∠C = 180

⇒ 35 + 52 + 3(x + 2) = 180

⇒ 87 + 3x + 6 = 180

⇒ 93 + 3x = 180

⇒ 3x = 87

⇒ x = 29

(b) As x = 29

⇒ m∠C = 3(29 + 2)

⇒ m∠C = 3 x 31

⇒ m∠C = 93°

ira [324]2 years ago

4 0

Answer:

x = 29

Angle C = 93°

Step-by-step explanation:

Since all of the interior angles of a triangle add up to 180° and we are given the values of angle A and angle B, we can find angle C by subtracting A and B from 180.

35 + 52 = 87

180 - 87 = 93

Thus, the measure of angle C is 93°.

Now that we know the measure of angle C, we can determine the value of x.

Set up an equation:

3(x + 2) = 93

3x + 6 = 93

3x = 87

x = 29

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Answer:

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2 years ago

Which statement about the following equation is true?

spayn [35]

The given expression is

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2 years ago

Read 2 more answers

A spacecraft is traveling with a velocity of v0x = 5320 m/s along the +x direction. Two engines are turned on for a time of 739

OlgaM077 [116]

Answer:

The velocities after 739 s of firing of each engine would be 6642.81 m/s in the x direction and 5306.02 in the y direction

Step-by-step explanation:

For a constant acceleration: $v_{f}=v_{0}+at$ , where $v_{f}$ is the final velocity in a direction after the acceleration is applied, $v_{0}$ is the initial velocity in that direction before the acceleration is applied, a is the acceleration applied in such direction, and t is the amount of time during where that acceleration was applied.
<em>Then for the x direction</em> it is known that the initial velocity is $v_{0x} =$ 5320 m/s, the acceleration (the applied by the engine) in x direction is $a_{x}$ 1.79 m/s2 and, the time during the acceleration was applied (the time during the engines were fired) of the is 739 s. Then: $v_{fx}=v_{0x}+a_{x}t=5320\frac{m}{s} +1.79\frac{m}{s^{2} }*739s=6642.81\frac{m}{s}$
In the same fashion, <em>for the y direction</em>, the initial velocity is $v_{0y} =$ 0 m/s, the acceleration in y direction is $a_{y}$ 7.18 m/s2, and the time is the same that in the x direction, 739 s, then for the final velocity in the y direction: $v_{fy}=v_{0y}+a_{y}t=0\frac{m}{s} +7.18\frac{m}{s^{2} }*739s=5306.02\frac{m}{s}$

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2 years ago

Gaveing out points for helpers!!

Alekssandra [29.7K]

Because the two angles add up to equal 90, you would make an equation set to equal 90. On the other end you add the measures of your angles together because they are adding up to equal 90. This would look like 2x+5+35=90 and you solve from here. Add like terms making it 2x+40=90 then you subtract 40 from both sides making it 2x=50 and then divide by 2 on both sides which leaves you with x=25.

3 0

2 years ago